3 g of activated charcoal was added to 50 mL of acetic acid solu

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 Multiple Choice QuestionsShort Answer Type

271.

A 10% solution (by mass) of sucrose in water has the freezing point of 269.15 K.Calculate the freezing point of 10% glucose in water if freezing point of pure water is273.15 K.

Given : (Molar mass of sucrose = 342 g mol–1) (Molar mass of glucose = 180 g mol–1)

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272.

Write one difference in each of the following:
Solution and Colloid

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273.

Calculate the freezing point of a solution containing 60 g of glucose (Molar mass = 180 g mol–1) in 250 g of water.
(Kf of water = 1.86 K kg mol–1)


274.

Give reasons for the following :

Measurement of osmotic pressure method is preferred for the determination of molar masses of macromolecules such as proteins and polymers.


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275.

Give reasons for the following:

Aquatic animals are more comfortable in the cold water than in warm water.


276.

Give reasons for the following:

Elevation of the boiling point of 1 M KCl solution is nearly double than that of 1 M sugar solution.


 Multiple Choice QuestionsMultiple Choice Questions

277.

18 g glucose (C6H12O6 ) is added to 178.2 g water. The vapor pressure of water (in torr) for this aqueous solution is:

  • 76.0

  • 752.4

  • 759.0

  • 759.0

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278.

The vapour pressure of acetone at 20oC is 185 torr. When 1.2 g of a non-volatile substance was dissolved in 100 g of acetone at 20oC, its vapour pressure was 183 torr. The molar mass (g mol-1 ) of the substance is:

  • 32

  • 64

  • 128

  • 128

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279.

3 g of activated charcoal was added to 50 mL of acetic acid solution (0.06N) in a flask. After an hour it was filtered and the strength of the filtrate was found to be 0.042 N. The amount of acetic acid adsorbed (per gram of charcoal) is:

  • 18 mg

  • 36 mg

  • 42 mg

  • 42 mg


A.

18 mg

The initial strength of acetic acid = 0.06N
Final strength = 0.042 N
Volume given = 50 mL
there Initial m moles of CH3COOH 
 = 0.06 x 50 = 3
Final m moles of CH3COOH 
 = 0.042 x 50 = 21
therefore, m moles of CH3COOH absorbed
 = 3-2.1
 = 0.9 m mol
Hence, mass of CH3COOH  absorbed per gram of charcoal
 = 

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280.

For the estimation of nitrogen 1.4g of an organic compound was digested by Kjeldahl's method and the evolved ammonia was absorbed in 60 mL of M/10 sulphuric acid. The unreacted acid required 20 mL of M/10 sodium hydroxide for complete neutralisation. The percentage of nitrogen in the compound is 

  • 6%

  • 10%

  • 3%

  • 3%

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