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 Multiple Choice QuestionsMultiple Choice Questions

331.

The freezing point of a 0.05 molal solution of a non- electrolyte in water is

  • -0.093° C

  • 1.86°C

  • 0.93° C

  • 0.093°C


332.

Solutions A, B, C and D are respectively 0.1 M glucose, 0.05 M NaCl, 0.05 M BaCl2 and 0.1 M AlCl3. Which one of the following pairs is isotonic?

  • A and B

  • B and C

  • A and D

  • A and C


333.

Copper is a divalent metal. The value of its electrochemical equivalent is 3.29 × 10-4 g. Its atomic mass is

  • 31.74 g

  • 63.5 g

  • 126.9 g

  • 15.87 g


334.

The vapour pressure of benzene at a certain temperature is 640 mm of Hg. A non-volatile and non-electrolyte solid weighing 2.175 g is added to 39.08 g of benzene. If the vapour pressure of the solution is 600 mm of Hg, what is the molecular weight of solid substance ?

  • 49.50

  • 59.60

  • 69.60

  • 79.82


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335.

Which of the following solutions will have highest boiling point ?

  • 0.1 M FeCl3

  • 0.1 M BaCl2

  • 0.1 M NaCl

  • 0.1 M urea (NH2CONH2)


336.

Maximum depression in freezing point is caused by

  • potassium chloride

  • sodium sulphate

  • magnesium sulphate

  • magnesium carbonate


337.

Which of the following is not a colligative property?

  • Elevation in boiling point

  • Lowering of vapour pressure

  • Osmotic pressure

  • Freezing point


338.

34.2 g of cane sugar is dissolved in 180 g of water. The relative lowering of vapour pressure will be

  • 0.0099

  • 1.1597

  • 0.840

  • 0.9901


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339.

According to Hess's law, the heat of reaction depends upon

  • initial condition of reactants

  • initial and final conditions of reactants

  • intermediate path of the reaction

  • end conditions of reactants


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340.

Ratio of loss in solvent to gain in CaCl2 tube is

  • p°p

  • pp°

  • p° - pp°

  • p - p°p


C.

p° - pp°

 Loss in the weight of solvent = p° - p

    Gain in the weight of CaCl2 tube = p°

 Loss in the weight of solventGain in the weight of CaCl2 tube = p° - pp°


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