The Ka of an acid is 3.2 x 10-5. The degree of dissociation of the acid at concentration of 0.2 M is
6.0 x 10-2
1.26 x 10-2
4.0 x 10-2
0.04 x 10-3
Addition of a non-volatile solute causes lowering in vapour pressure of a solvent from 0.8 atm to 0.2 atm. What is the
mole fraction of solvent?
0.25
0.75
0.50
Cannot be predicted
What would be the freezing point of aqueous solution containing 17g of C2H5OH in 1000 g of water?
0.34°C
0.0°C
-0.34°C
-0.69°C
D.
-0.69°C
Molality of C2H5OH (non- electrolyte solution)
Freezing point of the solution
= 0C - 0.686C
= 0.69C
The pH of a solution is 5.0. If H+ ion concentration is decreased 100 times. Then the solution will be :
neutral
more acidic
basic
of the same acidity
At a temperature, vapour pressure of pure benzene is 640 mm Hg. On dissolving 2.175 g of a non-volatile solid solute in 39.0 g benzene, vapour pressure of the solution if found to be 600 mm Hg. The molecular mass of solute is:
65.25
54.94
63.55
87.62
50 cm3 ethylene glycol is dissolved in 50 g water. Freezing point of solution is -34°C. Assuming ideal behaviour than density of ethylene glycol is (for water , Kf =1.86 K kg mol-1)
1.273 g/cm3
2.173 g/cm3
1.133 g /cm3
2.612 g/cm3
The average molar heat capacity at constant volume of gaseous mixture contained 2 moles of each of two ideal gases X (CV , m = R) and Y (CV , m = R)
2R
3R
4R
8R
How many grams of CaC2O4 will dissolve in distilled water to make one litre of saturated solution? Solubility product of CaC2O4 is 2.5 x 10-9 mol2 litre-2 and its molecular weight is 128
0.0640 gm
0.0032 gm
0.0128 gm
0.0064 gm
1 g of a non-volatile, non-electrolyte solute of molar mass 250 g/mol was dissolved in 51.2 g of benzene. If the freezing point depression constant , kf of benzene is 5.12 kg K mol-1 , the freezing point of benzene is lowered by :
0.3 K
0.5 K
0.2 K
0.4 K
A 6% solution of urea is isotonic with :
1M solution of glucose
0.05 M solution of glucose
6% solution of glucose
25% solution of glucose