How many litres of oxygen (at STP) are required for complete comb

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 Multiple Choice QuestionsMultiple Choice Questions

361.

What is the volume (in litres) of oxygen at STP required for complete combustion of 32 g of CH4?

(Molecular weight of CH4 is 16)

  • 44.8

  • 89.6

  • 22.4

  • 179.2


362.

250 mL of a sodium carbonate solution contains 2.65 g of Na2CO3. If 10 mL of this solution is diluted to one litre, what is the concentration of the resultant solution ?

  • 0.1 M

  • 0.001 M

  • 0.01 M

  • 10-4 M


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363.

How many litres of oxygen (at STP) are required for complete combustion of 39 g of liquid benzene? (Atomic weights: C = 12, O = 16, H = 1).

  • 84

  • 22.4

  • 42

  • 11.2


A.

84

C6H6 + 712O2 → 6CO2 + 3H2O

78 gm = 7.5 × 22.4 L

Volume of O2 required for 78 gm of C6H6 = 7.5 × 22.4 L

Volume of O2 required for 39 gm of C6H675 × 22.4 ×3978 = 84 L


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364.

X litre of carbon monoxide is present at STP. It is completely oxidized to CO2. The volume of CO2 formed is 11.207 litres. What is the value of X in litres?

  • 22.414

  • 11.207

  • 5.6035

  • 44.828


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365.

What is the volume (in litres) of oxygen required at STP to completely convert 1.5 mol of sulphur into sulphur dioxide?

  • 11.2

  • 22.4

  • 33.6

  • 44.8


366.

The concentration of a 100 mL solution containing X g of Na2CO3 (molecular wt. = 106) is Y M. The values of X and Y are respectively.

  • 2.12, 0.05

  • 1.06, 0.2

  • 1.06, 0.1

  • 2.12, 0.1


367.

One mole of fluorine is reacted with two moles of hot concentrated KOH. The products formed are KF, H2O and O2. The molar ratio of KF, H2O and O2 , respectively is

  • 1 : 1 : 2

  • 2 : 1 : 0.5

  • 1 : 2 : 1

  • 2 : 1 : 2


368.

The electrochemical equivalent of a metal is 'x' g coulomb-1. The equivalent weight of metal is

  • x

  • x × 96500

  • x96500

  • 1.6 × 1019 × x


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369.

grams of water is mixed in 69 g of ethanol. Mole fraction of ethanol in the resultant solution is 0.6. What is the value of x in grams?

  • 54

  • 36

  • 180

  • 18


370.

An organic compound containing C and H has 92.3% of carbon. Its empirical formula is

  • CH

  • CH3

  • CH2

  • CH4


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