64 g of an organic compound contains 24 g of carbon, 8 g of hydrogen and the rest oxygen. The empirical formula of the compound is
CH2O
C2H4O
CH4O
C2H8O
1f 20 mL of 0.4 N NaOH solution completely neutralises 40 mL of a dibasic acid, the molarity of the acid solution is
0.1 M
0.2 M
0.3 M
0.4 M
An organic compound containing C, H and N gives the following on analysis : C = 40%, H = 13.33% and N = 46.67%. What would be its empirical formula?
C2H7N
C2H7N2
CH4N
CH3N
C.
CH4N
Element | Percentage (x) | Atomic mass (y) | Molar ratio (x/y) | Simplest molar ratio |
C | 40 | 12 | = 3.33 | = 1 |
H | 13.33 | 1 | = 13.33 | = 4 |
N | 46.67 | 14 | = 3.33 | = 1 |
How many moles of O2 can be obtained by electrolysis of 90 g H2O?
5.0 mol
0.5 mol
2.5 mol
0.25 mol
An organic compound A contains 20% C, 46.66% N and 6.66% H. It gives NH3 gas on heating with NaOH. A can be
CH3CONH2
C6H5CONH2
NH2CONH2
CH3NHCONH2
The empirical formula of a compound is CH2. One mole of this compound has a mass 42g. Its molecular formula is
C3H6
C2H6
CH2
C2H2
Aqueous solutions of hydrogen sulphide and sulphur dioxide when mixed together, yield
sulphur trioxide and water
hydrogen and sulphurous acid
sulphur and water
hydrogen peroxide and sulphur