The volume of water to be added to N2 to prepare 500 mL

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 Multiple Choice QuestionsMultiple Choice Questions

411.

3 g of oxide of a metal is converted to chloride completely and it yielded 5 g of chloride. The equivalent weight of metal is

  • 12

  • 20

  • 33.25

  • 2.325


412.

4.9 g of H2SO4 is present in 100 mL solution. The molarity and normality of the solution will be

  • Molarity = 1M, Normality= 0.5N

  • Molarity = 1M, Normality= 0.25N

  • Molarity = 0.5M, Normality= 1N

  • Molarity = 2M, Normality= 3N


413.

0.0833 mole of a carbohydrate of empirical formula CH2O contains 1.00 g of hydrogen. The molecular formula of the carbohydrate is.

  • C5H10O5

  • C3H4O3

  • C12H22O11

  • C6H12O6


414.

When 50cm3 of 0.2N H2SO4 is mixed with 50 cm3 of 1N KOH, the heat liberated is

  • 11.46 kJ

  • 57.3 kJ

  • 573 kJ

  • 573 J


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415.

Heat liberated with 100 mL of 1 N NaOH is neutralised by 300 mL of 1 N HCl

  • 11.56 kJ

  • 5.73 kJ

  • 22.92 kJ

  • 17.19 kJ


416.

A solution contains 1.2046 x 1024 hydrochloric acid molecules in one dm3 of the solution. The strength of the solution is

  • 6N

  • 2N

  • 4N

  • 8N


417.

4g of copper was dissolved in concentrated nitric acid. The copper nitrate solution on strong heating gave 5 g of its oxide. The equivalent weight of copper is

  • 23

  • 32

  • 12

  • 20


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418.

The volume of water to be added to N2 to prepare 500 mL of N10 solution is

  • 450 mL

  • 100 mL

  • 45 mL

  • 400 mL


D.

400 mL

Let, x mL of HCl are taken, then

N1V1 = N2V2

12 × x = 110 × 50012 × x = 110 × 500

x = 100 mL

Hence, water needed to add = 500 - 100 = 400 mL


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419.

The equivalent weight of a certain trivalent element is 20. Molecular weight of its oxide is

  • 152

  • 56

  • 168

  • 68


420.

What is the volume of "20 volume H2O2" required to get 5000 cm3 of oxygen at STP?

  • 250 cm3

  • 50 cm3

  • 100 cm3

  • 125 cm3


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