Mass of 0.1 mole of methane is

• 1 g

• 16 g

• 1.6 g

• 0.1 g

80 g of oxygen contains as many atoms as in

• 80 g of hydrogen

• 1 g of hydrogen

• 10 g of hydrogen

• 5 g of hydrogen

433.

Excess of carbon dioxide is passed through 50 mL of 0.5 M calcium hydroxide solution. After the completion of the reaction, the solution was evaporated to dryness. The solid calcium carbonate was completely neutralised with 0.1 N hydrochloric acid. The volume of hydrochloric acid required is (Atomic mass of calcium = 40)

• 300 cm³

• 200 cm³

• 500 cm³

• 400 cm³

A bivalent metal has an equivalent mass of 32. The molecular mass of the metal nitrate is

• 182

• 168

• 192

• 188

A mixture of CaCl₂ and NaCl weighing 4.44 g is treated with sodium carbonate solution to precipitate all the Ca²⁺ ions as calcium carbonate. The calcium carbonate so obtained is heated strongly to get 0.56 g of Cao. The percentage of NaCl in the mixture (atomic mass of Ca = 40) is

• 75

• 30.6

• 25

• 69.4

A mixture of CaCl₂ and NaCl weighing 4.44 g is treated with sodium carbonate solution to precipitate all the calcium ions as calcium carbonate. The calcium carbonate so obtained is heated strongly to get 0.56 g of CaO. The percentage of NaCl in the mixture is (atomic mass of Ca = 40)

• 75

• 31.5

• 40.2

• 25

50 cm³ of 0.2 N HCl is titrated against 0.1 N NaOH solution. The titration was discontinued after adding 50 cm³ of NaOH. The remaining titration is completed by adding 0.5 N KOH. The volume of KOH required for completing the titration is 

• 12 cm³

• 10 cm³

• 21.0 cm³

• 16.2 cm³

The rms velocity of hydrogen is $\sqrt{7}$ times the rms velocity of nitrogen. If T is the temperature of the gas, which of the following is true?

• ${\mathrm{T}}_{{\mathrm{H}}_2} = \sqrt{7 } {\mathrm{T}}_{{\mathrm{N}}_2}$

• ${\mathrm{T}}_{{\mathrm{N}}_2} = {\mathrm{T}}_{{\mathrm{H}}_2}$

• ${\mathrm{T}}_{{\mathrm{N}}_2} = \sqrt{7} {\mathrm{T}}_{{\mathrm{H}}_2}$

• ${\mathrm{T}}_{{\mathrm{N}}_2} = 2{\mathrm{T}}_{{\mathrm{H}}_2}$

50 cm³ of 0.2 NHCl is titrated against 0.1 N NaOH solution. The titration is discontinued after adding 50 cm³ of NaOH.The remaining titration is completed by adding 0.5 N KOH. The volume of KOH required for completing the titration is

• 12 cm³

• 10 cm³

• 25 cm³

• 10.5 cm³

1 g of silver gets distributed between 10 cm³ of molten zinc and 100 cm³ of molten lead at 800°C. The percentage of silver in the zinc layer is approximately

• 89

• 91

• 97

• 94