A bivalent metal has an equivalent mass of 32. The molecular mass

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

551.

A cylinder of compressed gas contains nitrogen and oxygen in the ratio of 3:1 by mole. The total mass of the gas mixture if the cylinder is known to contain 2.5 x 10g of oxygen will be:

  • 8 x 103 g

  • 9 x 10g

  • 9 x 103 g

  • 8 x 102 g


552.

Forty millilitre of CO was mixed 100 mL of O2 and the mixture was exploded. On cooling, the reaction mixture was shaken with KOH. What volume of gas is left?

  • 80 ml of O2

  • 60 ml of O2

  • 80 ml of CO2

  • 50 ml of CO2


553.

Arrange the following (I to IV) in the order of increasing masses:

I. 0.5 mole of O3

II. 0.5 g atom of oxygen

III. 3.011 x 1023 mlecules of O2

IV. 5.6 l of CO2 at STP

  • II < IV < III < I

  • IV < III < I < II

  • II < I < IV < III

  • I < II < III < IV


554.

75 c.c. of N/5 H2SO4, 10 c.c. of N/2 HCl and 30 c.c. of N/10 HNO3 are mixed together. The strength of the resulting acid mixture is:

  • 0.1N

  • 0.2N

  • 0.3N

  • 0.4N


Advertisement
555.

One mole of FeC2O4 is oxidised by x moles of Cr2O72- in acidic medium , x is:

  • 0.5

  • 1.0

  • 1.5

  • 2.0


556.

One gram of mass is equal to :

  • 9 x 1020 ergs

  • 7 x 1015 ergs

  • 5 x 1010 ergs

  • 3 x 105 ergs


557.

Vapour density of a volatile substance is 4 (CH4 = 1). Its molecular weight would be:

  • 2

  • 8

  • 64

  • 128


558.

20 mL of 0.5 N HCl and 35 mL of 0.1 N NaOH are mixed. The resulting solution will :

  • be neutral

  • be basic

  • turn phenolphthalein solution pink

  • turn methyl orange red


Advertisement
Advertisement

559.

A bivalent metal has an equivalent mass of 32. The molecular mass of the metal nitrate is :

  • 182

  • 168

  • 192

  • 188


D.

188

Atomic mass of the metal = 32 x 2 = 64

Formula of metal nitrate= M(NO3)2

 Molecular mass = 64 + (14 + 3 x 16) x 2 = 188


Advertisement
560.

35.4 mL of HCl is required for the neutralization of a solution containing 0.275 g of sodium hydroxide. The normality of hydrochloric acid is?

  • 0.97 N

  • 0.142 N

  • 0.194 N

  • 0.244 N


Advertisement