Which of the following sets of quantum numbers is correct for an

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 Multiple Choice QuestionsMultiple Choice Questions

381.

Which one of the following transitions of an electron in hydrogen atom emits radiation of the lowest wavelength?

  • n2 = ∞ to n1=2

  • n2= 4 to n1 =3

  • n2= 2 to n1 =1

  • n2 = 5 to n1=3


382.

Which one of the following conditions is incorrect for a well behaved wave function (Ψ)?

  • Ψ must be fine

  • Ψ must be single valued

  • Ψ must be infinite

  • Ψ must be continuous


383.

The electron affinity values of elements A, B, C and D are respectively -135, -60, -200 and -348 kJ mol-1. The outer electronic configuration of element B is

  • 3s2 3p5

  • 3s3p4

  • 3s2 3p3

  • 3s2 3p2


384.

Which one of the following frequencies of radiation (in Hz) has a wavelength of 600 nm?

  • 2.0 × 1013 

  • 5.0 × 1016 

  • 2.0 × 1014 

  • 5.0 × 1014 


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385.

According to Bohr's theory which one of the following values of angular momentum of hydrogen atom is not permitted?

  • 1.25 hπ

  • hπ

  • 1.5  hπ

  • 0.5 hπ


386.

The number of radial nodes of 3s and 2p orbitals respectively are

  • 0, 2

  • 2, 0

  • 1, 2

  • 2, 1


387.

The basis of quantum mechanical model of an atom is

  • angular momentum of electron

  • quantum numbers

  • dual nature of electron

  • black body radiation


388.

The quantum number which explains the line spectra observed as doublets in case of hydrogen and alkali metals and doublets and triplets in case of alkaline earth metals is

  • spin

  • azimuthal

  • magnetic

  • principal


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389.

A compound absorbs light in the wavelength region 490-500 nm. Its complementary colour is

  • red

  • blue

  • orange

  • blue-green


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390.

Which of the following sets of quantum numbers is correct for an electron in 3d-orbital?

  • n = 3; l = 2; m = -3; s = +12

  • n = 3; l = 3; m = +3; s = -12

  • n = 3; l = 2; m = -2; s = +12

  • n = 3; l = 2; m = -3; s = -12


C.

n = 3; l = 2; m = -2; s = +12

Among the given sets of quantum numbers, set c is the correct option.

Step I. The value of n for the given electron is 3. 

 n = 3

Step II. Value of l should never be greater than n and for the given case, it is 0 to (n - 1).

 l = (n - 1) = (3 - 1) = 2

Step III. Value of m varies from -l to +l, including 0. 

 m = -2, -1, 0, +1 and +2.

Step IV. Value of s may be +12 (clockwise) or -12 (anticlockwise).

 For, 3d electron, s = +12


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