The element with the electronic configuration 1s2 2s22p63s23p63d104s1 is
Cu
Ca
Cr
Co
A.
Cu
As the element copper has atomic number= 29. So, electronic configuration
= 1s2 2s2 2p6 3s2 3p6 3d10 4s1=[Ar] 3d10 4s1
Which of the following electron has minimum energy?
n = 4; l = 0; m= 0; s = +
n= 4; l= 1; m = ±1; s = +
n = 5; l = 0; m = 0; s = +
n = 3; l = 2; m = -2; s = +
How many emission spectral lines are possible when hydrogen atom is excited to nth energy level?
Which of the following corresponds to the energy of the possible excited state of hydrogen?
-13.6 eV
13.6 eV
-3.4 eV
3.4 eV
The quantum number of four electrons are given below:
I. n = 4 | l = 2 | ml = -2 | ms = - |
II. n = 3 | l = 2 | ml = 1 | ms = + |
III. n = 4 | l = 1 | ml = 0 | ms = + |
IV. n = 3 | l = 1 | ml = 1 | ms = - |
The correct order of these increasing energies will be:
IV > III > II > I
I > II > III > IV
I > III > II > IV
IV > II > III > I
The correct order of the spin only magnetic moment of metal ions in the following low spin complexes, [V(CN)6]4-, [Fe(CN)6]4-, [Ru(NH3)6]3+ and [Cr(NH3)6]2+ is
V2+ > Cr2+ > Ru3+ > Fe2+
V2+ > Ru3+ > Cr2+ > Fe2+
Cr2+ > V2+ > Ru3+ > Fe2+
Cr2+ > Ru3+ > Fe2+ > V2+
Which one of the following about an electron occupying the 1s orbital in a hydrogen atom is incorrect? (The Bohr radius is represented by a0).
The electron can be found at a distance 2a0 from the nucleus.
The probability density of finding the electron is maximum at the nucleus.
The total energy of the electron is maximum when it is at a distance a0 from the nucleus.
The magnitude of the potential energy is double that of its kinetic energy on a an average.
If p is the momentum of the fastest electron ejected from a metal surface after the irradiation of light having wavelength λ, then for 1.5 p momentum of the photoelectron, the wavelength of the light should be: (Assume kinetic energy of ejected photoelectron to be very high in comparison to work function) :