Which of the following electron has minimum energy?
n = 4; l = 0; m= 0; s = +
n= 4; l= 1; m = ±1; s = +
n = 5; l = 0; m = 0; s = +
n = 3; l = 2; m = -2; s = +
How many emission spectral lines are possible when hydrogen atom is excited to nth energy level?
C.
Number of spectral lines =.
n is the orbital in which the elctrons exist.
Which of the following corresponds to the energy of the possible excited state of hydrogen?
-13.6 eV
13.6 eV
-3.4 eV
3.4 eV
The quantum number of four electrons are given below:
I. n = 4 | l = 2 | ml = -2 | ms = - |
II. n = 3 | l = 2 | ml = 1 | ms = + |
III. n = 4 | l = 1 | ml = 0 | ms = + |
IV. n = 3 | l = 1 | ml = 1 | ms = - |
The correct order of these increasing energies will be:
IV > III > II > I
I > II > III > IV
I > III > II > IV
IV > II > III > I
The correct order of the spin only magnetic moment of metal ions in the following low spin complexes, [V(CN)6]4-, [Fe(CN)6]4-, [Ru(NH3)6]3+ and [Cr(NH3)6]2+ is
V2+ > Cr2+ > Ru3+ > Fe2+
V2+ > Ru3+ > Cr2+ > Fe2+
Cr2+ > V2+ > Ru3+ > Fe2+
Cr2+ > Ru3+ > Fe2+ > V2+
Which one of the following about an electron occupying the 1s orbital in a hydrogen atom is incorrect? (The Bohr radius is represented by a0).
The electron can be found at a distance 2a0 from the nucleus.
The probability density of finding the electron is maximum at the nucleus.
The total energy of the electron is maximum when it is at a distance a0 from the nucleus.
The magnitude of the potential energy is double that of its kinetic energy on a an average.
If p is the momentum of the fastest electron ejected from a metal surface after the irradiation of light having wavelength λ, then for 1.5 p momentum of the photoelectron, the wavelength of the light should be: (Assume kinetic energy of ejected photoelectron to be very high in comparison to work function) :