The correct sets of quantum numbers which represents the highest

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 Multiple Choice QuestionsMultiple Choice Questions

581.

Total number of atoms represented by the compound CuSO4 · 5H2O is :

  • 27

  • 21

  • 5

  • 8


582.

When electrons are trapped into the crystal in anion vacancy, the defect is known as :

  • Schottky defect

  • Frenkel defect

  • stoichiometric defect

  • F-centres


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583.

The correct sets of quantum numbers which represents the highest energy level in an atomis:

  • n=4 , l=0 , m=0 , s = + 12

  • n=3 , l=0 , m=0 , s = + 12

  • n=3 , l=1 , m=1 , s = + 12

  • n=3 , l=2 , m= -1 , s = + 12


D.

n=3 , l=2 , m= -1 , s = + 12

The order of energy of orbitals can be calculated from (n + 1) rule. The lower the value of (n +l) For an orbital, lower is its energy. If two orbitals have same (n+J) value, the orbital with lower value of n has lower energy.

(a) n+l = 4  (b) n+l = 3

(c) n+l = 4   (d) n+l = 4

 

 The correct set which represents the highest energy level is n = 3 , l = 2 , m = -2 and s = + 12


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584.

Wave number of a spectral line for a given transition is xcm-1 for He+ then its value for Be+ (iso electronic of H+) for same transition is:

  • x cm-1

  • 4x cm-1

  • x4cm-1

  • 2x cm-1


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585.

Ratio of radii of second and first Bohr orbits of H atom is

  • 2

  • 4

  • 3

  • 5


586.

India conducted an underground nuclear test at

  • Narora

  • Tarapur

  • Pushkar

  • Pokharan


587.

Dual nature of particle was-given by

  • Bohr theory

  • Thomson model

  • Heisenberg principle

  • de-Broglie equation


588.

A golf-ball weigh 40.0 gm. If it is moving with a velocity of 20.0 ms-1, it's de-Broglie wavelength is

  • 1.66 x 10-34 nm

  • 8.28 x 10-32 nm

  • 8.28 x 10-25 nm

  • 1.66 x 10-24 nm


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589.

Which is the shortest wavelength line in the Lyman series of the hydrogen spectrum? (R= 1.097 x 10-2 nm-1)

  • 94.21 nm

  • 91.16 nm

  • 911.6 nm

  • 933.6 nm


590.

Which of the following order of ionisation energy is correct?

  • B < Be < N < C

  • Be > B > C > N

  • B < Be < C < N

  • Be < B < C < N


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