146. Analysis shows that nickel oxide has formula Ni 0.98 O_1.00 What fractions of Nickel exist as Ni²⁺ and Ni³⁺ ions? 

Formula is Ni_0.98O_1.00
So the ration of Ni : O = 98:100
So if there are 100 atoms of oxygen then 98 atoms of Ni,

Let number of atoms of Ni⁺² = x
Then number of atoms of Ni⁺³ = 98–x
Charge on Ni = charge on O
So that oxygen has charge –2
3(98–x) + 2x = 2 (100)
294 –3x +2x = 200
–x = – 94
x = 94

Percentage of Ni⁺² = (atom of Ni⁺²/total number of atoms of Ni)100
=100(94/98)x100
= 96%

Percentage of Ni⁺³
=100 – Ni⁺²
=100 – 96
= 4 %