162.
Calculate the density of silver which crystallizes in a face centred cubic lattice with unit cell length 0.4086 nm (At. mass of Ag = 107.88)
Solution:
We have given that
Unit cell length,
a = 0.40806 nm = 4.086 x 10-10 m
If fcc lattice the number of atoms per unit cell,
i.e. Z = 4
M for Ag = 107.88 g mol-1
Density of Ag, d =
Thus the density of silver is 1.051 x 104 kgm-3
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