What is the formula of a compound in which the element Y forms ccp lattice and atoms of X occupy 1/3rd of tetrahedral voids?
Number of tetrahedral voids formed = 2 x Number of atoms of element Y
Number of atoms of element Y in the ccp unit cell = 4
Number of tetrahedral voids formed = 2 x 4 = 8
Number of tetrahedral voids occupied by atoms of X = 1/3x8
Ratio of the numbers of atoms of X and Y = 8/3: 4 =2: 3
Hence, the formula of the compound is X2Y3.
An element with molar mass 27 g mol-1 forms a cubic unit cell with edge length 4.05 x 10-8 cm . If its density is 2.7 g cm-3 , what is the nature of the cubic unit cell?
An element with density 11.2 g cm-3 forms a f.c.c. lattice with edge length of 4 x10-8
Calculate the atomic mass of the element. (Given: NA = 6.022x 10-23 (mol-1)