A metal has a fcc lattice. The edge length of the unit cell is 40

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 Multiple Choice QuestionsMultiple Choice Questions

501.

Suppose the mass of a single Ag-atom is m. Ag metal crystallises in fcc lattice with unit cell of length a. The density of Ag metal in terms of a and 'm' is

  • 4ma3

  • 2ma3

  • ma3

  • m4a3


502.

Crystalline solids have

  • short range order

  • long range order

  • anisotropic distribution

  • All of these.


503.

The number of carbon atoms per unit cell of diamond unit cell is

  • 4

  • 8

  • 6

  • 1


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504.

A metal has a fcc lattice. The edge length of the unit cell is 404 pm. The density of the metal is 2.72 g cm3. The molar mass of the metal is (NA  vogadro's constant = 6.02x 1023 mol-1).

  • 40 g mol-1

  • 30 g mol-1

  • 27g mol-1

  • 20 g mol-1


C.

27g mol-1

Given, cell is fcc, so Z = 4
Edge length, a= 404 pm= 4.04 x 10-8 cm
Density of metal, d= 2.72 g cm-3
NA = 6.02 x 1023 mol-1
Molar mass of the metal, M=?
We know that,

density, d =Z × Ma3· NA therefore ,M =d·a3·NAZ     = 2.72 ×( 4.04 ×10-8)3×6.02 ×10234     = 27 g mol-1


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505.

What is the co-ordination number of body centred cube ?

  • 8

  • 6

  • 4

  • 12


506.

A compound is formed by cation C and anion A. The anions form hexagonal close packed (hcp) lattice and the cations occupy 75% of octahedral voids. The formula of the compound is :

  • C3A2

  • C3A4

  • C4A3

  • C2A3


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