[Ti(H2O)6]3+ is coloured while [Sc(H2O)6]3+ is colourle
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    The d-And-f-Block Elements

    Multiple Choice QuestionsShort Answer Type

    61. Why do transition elements exhibit paramagnetism?
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    62.

    Why does Mn(II) ion show maximum paramagnetic character amongst bivalent ions of first transition series?

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    63.

    Calculate the magnetic moment of Fe3+ ion (at. no. of Fe = 26).

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    64. Why Zn2+ salts are white while Ni2+ salts are blue?
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    65. Why Zn2+ salts are white while Cu2+ salts are blue?
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    66. [Ti(H2O)6]3+ is coloured while [Sc(H2O)6]3+ is colourless. Explain.

    Ti has the electronic configuration [Ar] 3d2. In [Ti(H2O)6]3+ complex it is present as Ti3+ which has one unpaired electron in 3d orbital.Thus d-d transition is possible only in Ti(H2O)63+ and thereby it shows colour And also  it undergoes d2sp3 (octahedral) hybridization to accomodate 6 pairs of water. 
    So the complex is octahedral in shape, will be coloured and paramagnetic due to presence of one unpaired electron. 
    Sc has the electronic configuration [Ar]3d1 . Since it is present in the complex [Sc(H2O)6]3+ as Sc3+ it has no unpaired electron. It will also undergo d2sp3 hybridization to accomodate 6 pairs of electrons from water. 
    So it is also octahedral, colourless and diamagnetic due to absence of unpaired electron.
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    67. Giving reasons indicate which one of the following would be coloured?
    Cu+, V2+, Sc3+ Ni2+ (At. No., Cu = 29, V = 23, Sc = 21, Ni = 28)
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    68.

    Why Cd2+ salts are white? 

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    69. Cu+ is colourless but Cu2+ is coloured. Why?
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    70. Which of the following do you expect to be coloured and why? Cr+, Cu+?
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