Short Answer TypeWrite the formula of the compound in which the transition metal Mn is in +7 oxidation state.
Describe the oxidation states and variable valencies of elements of 3d series.
The ability of the transition metals to exhibit variable valency is generally attributed to the availability of more electrons in the (n-1)d orbitals which are closer to the outermost ns orbital in energy levels.
Transition metals have electrons of similar energy in both the 3d and 4s levels. This means that one particular element can form ions of roughly the same stability by losing different numbers of electrons. Thus, all transition metals from titanium to copper can exhibit two or more oxidation states in their compounds.
Oxidation states of some Transition Metals:
Titanium- +2, +3, +4
Vanadium- +2, +3, +4, +5
Chromium- +2, +3, +6
Manganese- +2, +3, +4, +5, +6, +7
Iron- +2, +3
Cobalt- +2, +3
Nickel- +2, +3, +4
Copper- +1, +2
When Transition Metals form positive ions they loose their electrons from the 4s sub-shell first, then the 3d sub-shell
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