The Orange colour of Cr2O72– ion changes to yellow when treated with an
alkali. Why ?
Give reason:
Iron has a higher enthalpy of atomization than that of copper.
Transition metal has the high heat of atomisation due to the presence of strong metallic bond which arises due to the presence of an unpaired electron in the (n - 1) d subshell. This is because the atoms in these elements are closely packed and held together by strong metallic bonds. The metallic bond is formed as a result of the interaction of electrons in the outermost shell. Greater the number of valence electrons, stronger is the metallic bond.
The pair in which phosphorous atoms have a formal oxidation state of +3 is:
Pyrophosphorous and hypophosphoric acids
Orthophosphorous and hypophosphoric acids
Pyrophosphorous and pyrophosphoric acids
Pyrophosphorous and pyrophosphoric acids
Match the catalysis to the correct processes.
Catalyst | Process |
(A)TiCl3 | (i) Wacker Process |
(B) PdCl2 | (ii) Ziegler -Natta |
(C) CuCl2 | (iii) Contact process |
(D) V2O5 | (iv)Deacon's process |
(A)- (iii), (B)-(ii), (C)-iv, (D)- (i)
(A) - (ii), (B) - (i), (C) -(iv), (D) - (iii)
(A)- (ii), (B)- (iii), (C)- (iv), (D) - (i)
(A)- (ii), (B)- (iii), (C)- (iv), (D) - (i)
The equation which is balanced and represents the correct product(s) is
Li2O + 2KCl → 2LiCl + K2O
[COCl(NH3)5]+ + 5H+ → Co2+
[Mg(H2O)6]2+ + (EDTA)4- [Mg(EDTA)]2+ + 6H2O
[Mg(H2O)6]2+ + (EDTA)4- [Mg(EDTA)]2+ + 6H2O