Consider the hydrated ions of Ti2+,v2+, Ti3+ and Sc3+ The correct order of their spin only magnetic moments is :
Ti3+ < Ti2+< Sc3+< V2+
Vi2+ <Ti2+< Ti3+ < Sc3+
Sc3+< Ti3+< Ti2+<V2+
Sc3+< Ti3+< V2+< Ti2+
Three complex [CoCl(NH3)5]2+ (I)[Co(NH3)5H2O]3+(II) and [Co(NH3)6]3+(III) absorb light in the visible region . the correct order of the wavelength of light absorbed by them is :
II > I > III
III > I > II
I> II> III
III> II> I
The correct order of the first ionization enthalpies is :
Ti < Mn < Ni < Zn
Mn < Ti < Zn < Ni
Ti < Mn < Zn < Ni
Zn < Ni < Mn < Ti
The highest possible oxidation states of uranium plutonium , respectively are
6 and 7
7 and 6
4 and 6
6 and 4
When copper is heated with conc. HNO3 it produces
Cu(NO3)2 and NO
Cu(NO3)2, NO and NO2
Cu(NO3)2 and N2O
Cu(NO3)2 and N2O
Which one of the following statements is correct when SO2 is passed through acidified K2Cr2O7 solution?
The solution is decolourized
SO2 is reduced
Green Cr2(SO4)3 is formed
The solution turns blue
Because of lanthanoid contraction, of elements which of the following elements have nearly same atomic radii ? (Number in the parenthesis are atomic number).
Ti (22) and Zr(40)
Zr(40) and Nb (41)
Zr (40) and Hf (72)
Zr (40) and Hf (72)
C.
Zr (40) and Hf (72)
Because of the lanthanoid contraction Zr (atomic radii 160 pm) and Hf (atomic radii 158 pm) have nearly same atomic radii.
Lanthanoids include the elements from lanthanum La (Z=57) to lutetium Lu(Z =71).Zirconium Zr (40) belong to the second transition series (4d) and Hf (72) belongs to third transition series (5d). Lanthanoid contraction is associated with the intervention of the 4f orbitals which are filled before the 5d- series of elements starts. The filling of 4f if orbitals before 5d orbitals result in a regular decrease in atomic radii which compensates the expected increases in atomic size with increasing atomic number. As a result of this lanthanoid contraction, the elements of second and third transition series have almost similar atomic radii.
In acidic medium,H2O2 changes Cr2O72- to CrO5 which has two (-O-O-) bonds. Oxidation state of Cr in CrO3 is
+5
+3
+6
+6
Reason of lanthanoid contraction is
negligible Screening effect of 'f' orbitals
increasing the nuclear charge
decreasing the nuclear charge
decreasing the nuclear charge