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 Multiple Choice QuestionsMultiple Choice Questions

561.

The IUPAC symbol for the element with atomic number 119 would be:

  • uun

  • uue

  • uuh

  • une


562.

Consider the hydrated ions of Ti2+,v2+, Ti3+ and Sc3+ The correct order of their spin only magnetic moments is :

  • Ti3+ < Ti2+< Sc3+< V2+

  • Vi2+ <Ti2+< Ti3+ < Sc3+

  • Sc3+< Ti3+< Ti2+<V2+

  • Sc3+< Ti3+< V2+< Ti2+


563.

Three complex [CoCl(NH3)5]2+ (I)[Co(NH3)5H2O]3+(II) and [Co(NH3)6]3+(III) absorb light in the visible region . the correct order of the wavelength of light absorbed by them is :

  • II > I > III

  • III > I > II

  • I> II> III

  • III> II> I


564.

The correct order of the first ionization enthalpies is :

  • Ti < Mn < Ni < Zn

  • Mn < Ti < Zn < Ni

  • Ti < Mn < Zn < Ni

  • Zn < Ni < Mn < Ti


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565.

The highest possible oxidation states of uranium plutonium , respectively are

  • 6 and 7

  • 7 and 6

  • 4 and 6

  • 6 and 4


566.

When copper is heated with conc. HNO3 it produces

  • Cu(NO3)2 and NO

  • Cu(NO3)2, NO and NO2

  • Cu(NO3)2 and N2O

  • Cu(NO3)2 and N2O

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567.

Which one of the following statements is correct when SO2 is passed through acidified K2Cr2O7 solution?

  • The solution is decolourized

  • SO2 is reduced

  • Green Cr2(SO4)3 is formed

  • The solution turns blue


568.

Because of lanthanoid contraction, of elements which of the following elements have nearly same atomic radii ? (Number in the parenthesis are atomic number).

  • Ti (22) and Zr(40)

  • Zr(40) and Nb (41)

  • Zr (40) and Hf (72)

  • Zr (40) and Hf (72)

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569.

In acidic medium,H2O2 changes Cr2O72- to CrO5 which has two (-O-O-) bonds. Oxidation state of Cr in CrO3 is 

  • +5

  • +3

  • +6

  • +6

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570.

Reason of lanthanoid contraction is

  • negligible Screening effect of 'f' orbitals

  • increasing the nuclear charge

  • decreasing the nuclear charge

  • decreasing the nuclear charge


A.

negligible Screening effect of 'f' orbitals

Lanthanoid contraction is the regular decrease in atomic and ionic radii of lanthanides. This is due to the imperfect shielding [or poor screening effect] of f-orbitals due to their diffused shape, which unable to counterbalance the effect of the increased nuclear charge. Hence, the net result is a contraction in size of lanthanoids.

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