Considering the parameters such as bond dissociation enthalpy, el

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 Multiple Choice QuestionsShort Answer Type

391. Why does O3 act as a powerful oxidising agent?
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392. How is O3 estimated quantitatively?
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393. What happens when sulphur dioxide is passed into aqueous solution of Fe (III) salt?
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394. Comment on the nature of two S-O bonds formed in SO2 molecule. Are the two S-O bonds in this molecule equal?
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395. How is the presence of SO2 detected?
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396. Mention three areas in which H2SO4 plays an important role.
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397. Write the conditions to maximise the yield of H2SO4 by contact process.
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398. Why is Ka2 < < Ka, for H2SO4 in water?
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399. Considering the parameters such as bond dissociation enthalpy, electron gain enthalphy and hydration enthalpy compare the oxidising power of F2 and Cl2.


Fluorine is a much stronger oxidizing agent than chlorine. The oxidizing power depends on three factors.
1. Bond dissociation energy
2. Electron gain enthalpy
3. Hydration enthalpy
The electron gain enthalpy of chlorine is more negative than that of fluorine. However, the bond dissociation energy of fluorine is much lesser than that of chlorine. Also, because of its small size, the hydration energy of fluorine is much higher than that of chlorine. Therefore, the latter two factors more than compensate for the less negative electron gain enthalpy of fluorine. Thus, fluorine is a much stronger oxidizing agent than chlorine.
 
The oxidising power decreases from F2 to Cl2,. The decreasing oxidising power of the halogens in aqueous solution down the group (fluorine to chlorine) is evidnent from their standard electrode potentials which are dependent on the parameters indicates below:
             1/2 × 2 (g) 1/2  diss H° × (g) egH° H-(g)   hydH° × -(aq)
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400. Give two examples to show the anomalous behaviour of fluorine.
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