Calculate the maximum work obtained when 0.75 mol of an ideal gas expands isothermally and reversibly at 27°C from a volume of 15L to 25L.
We have given,
Volume (V2) = 25L
Volume (V1) =15L
Number of moles =0.75
using the equation,
Substituting the values, we have,
If water vapour is assumed to be a perfect gas,
molar enthalpy change for vapourisation of 1 mol of water at 1bar and 100°C is 41kJ mol–1. Calculate the internal energy change, when
(i) 1 mol of water is vaporised at 1 bar pressure and 100°C.
Derive mathematical form of First law of Thermodynamics.
Or
Derive the relationship between heat, internal energy and work.