The heats of combustion of carbon and carbon monoxide are −393

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 Multiple Choice QuestionsShort Answer Type

301.

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#13 {main}</pre>what will be increment straight S?

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302.

For the reaction,
   2 Cl left parenthesis straight g right parenthesis space rightwards arrow space Cl subscript 2 left parenthesis straight g right parenthesis comma space what space are space the space signs space of space increment straight H space and space increment straight S ?

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 Multiple Choice QuestionsMultiple Choice Questions

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303.

The heats of combustion of carbon and carbon monoxide are −393.5 and −283.5 kJ mol−1, respectively. The heat of formation (in kJ) of carbon monoxide per mole is:

  • 676.5

  • -676.5

  • -110.5

  • -110.5


C.

-110.5

C(s) + O2 (g) → CO2 (g); ΔH = -393.5 kJ mol-1 ... (i)

CO + O2/2 → CO2 (g); ΔH = - 283.5 kJ mol-1 ....(ii)
On subtracting Eq. (ii) from Eq. (i), we get

C (s) + O2/2 (g) → CO (g)


ΔH = (-393.5 + 283.5) kJ mol-1 = - -110 kJ mol-1

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304.

The following reaction is performed at 298 K
2NO(g) + O2 (g) ⇌ 2NO2 (g)
The standard free energy of formation of NO (g) is 86.6 kJ/mol at 298 K. What is the standard free energy of formation of NO2 (g) at 298 K? (KP = 1.6 x 1012)

  • R (298) In (1.6 x 1012)-86600

  • 86600 + R (298) In (1.6 x 1012)

  • 86600 - In(1.6 x 1012)/R(298)

  • 86600 - In(1.6 x 1012)/R(298)

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305.

The standard Gibbs energy change at 300 K for the reaction, 2A  ⇌ B +C is 2494.2J at a given time, the composition of the reaction mixture isleft square bracket straight A right square bracket space equals space 1 half comma space left square bracket straight B right square bracket space equals 2 and left square bracket straight C right square bracket space equals space 1 half, The reaction proceeds in the [R= 8.314 JK/mol, e = 2.718]

  • forward direction because Q>Kc

  • reverse direction because Q>Kc

  • forward direction because Q < Kc

  • forward direction because Q < Kc

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306.

For the complete combustion of ethanol, C2H5OH (l) + 3O2 (g) → 2CO2 (g) + 3H2(l), the amount of heat produced as measured in a bomb calorimeter, is 1364.47 kJ mol-1 at 25oC. Assuming ideality the enthalpy of combustion, CH, for the reaction will be (R = 8.314 JK-1 mol-1)

  • -1366.95 kJ mol-1

  • -1361.95 kJ mol-1

  • -1460.50 kJ mol-1

  • -1460.50 kJ mol-1

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307.

A piston filled with 0.04 mol of an ideal gas expands reversibly from 50.0 mL to 375 mL at a constant temperature of 37.00C. As it does so, it absorbs 208J of heat. The values of q and w for the process will be:(R = 8.314 J/mol K) ( ln 7.5 = 2.01)

  • q =+208J, W = - 208 J

  • q =-208 J, W =-208 J

  • q=-208J, W = +208 J

  • q=-208J, W = +208 J

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308.

The incorrect expression among the following is

  • fraction numerator increment space straight G subscript system over denominator increment straight G subscript total end fraction space equals space minus straight T
  • In isothermal process

    straight W subscript reversible space equals negative nRT space ln straight V subscript straight f over straight V subscript straight i

  • In space straight K space equals space fraction numerator increment straight H to the power of straight o minus straight T increment straight S over denominator RT end fraction
  • In space straight K space equals space fraction numerator increment straight H to the power of straight o minus straight T increment straight S over denominator RT end fraction
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309.

The standard reduction potentials for Zn2+/ Zn, Ni2+/ Ni, and F2+/ Fe are –0.76, –0.23 and –0.44 V respectively. The reaction X + Y2+ → X 2+ + Y will be spontaneous when

  • X = Ni, Y = Fe

  • X = Ni, Y = Zn

  • X =Fe, Y= Zn

  • X =Fe, Y= Zn

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310.

The entropy change involved in the isothermal reversible expansion of 2 moles of an ideal gas from a volume of 10 dm3 to a volume of 100 dm3 at 27°C is

  • 38.3 J mol-1 K-1

  • 35.8 J  mol-1 K-1

  • 32.3 J  mol-1 K-1

  • 32.3 J  mol-1 K-1

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