Heat of neutralization of HCl and NaOH is from Chemistry Thermod

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 Multiple Choice QuestionsMultiple Choice Questions

461.

In a reversible isothermal process, the change in internal energy is

  • zero 

  • positive

  • negative

  • None of these


462.

Based on the following thermochemical equations

H2O (g) + C(s) → CO (g) + H2 (g); H = 131 kJ

CO (g) + 12 O2(g) → CO2 (g); H = -282 kJ

H2 (g) + 12O2 (g) → H2O (g); H =-242 kJ

C (s) + O2 (g) → CO(g); H = X kJ

the value of X will be

  • -393 kJ

  • -655 kJ

  • +393 kJ

  • +655 kJ


463.

Which of the following relationships is correct?

  • k=TS°-H°RT

  • k=H°-TS°RT

  • ln k=H°-TS°RT

  • ln k=TS°-H°RT


464.

Which of the following represents the first law of thermodynamics?

  • U = q + W

  • U = p . V

  • U = H + P.V

  • H = q + W


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465.

Heat of neutralization of HCl and NaOH is

  • -13.7 kcal

  • -13.7 J

  • -13.7 kJ

  • None of these


A.

-13.7 kcal

The heat of neutralisation of a strong acid (HCl) and a strong base (NaOH) is always -13.7 kcal or -57.5 kJ.


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466.

Which is true for a cyclic process?

  • ΔE= 0

  • ΔE= q- W

  • q =W

  • All of these


467.

When solid melts, there will be

  • a decrease in enthalphy

  • a decrease in free energy

  • a decrease in entropy

  • all the above factors remain constant


468.

To convert 94 g of ice at 0°C into 94g of vapour at 100° C, the quantity of coal (90% carbon) required is : (ΔHc of carbon = -94 k cal mol-1);latent heat of fusion = + 80 cal per gm; latent heat ofvaporisation=+ 540 cal per gm; specificheat of water = 1 cal per gm per °C).

  • 94g

  • 80g

  • 9.4g

  • 9.6 g


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469.

When 1 M H2SO4 is completely neutralized by NaOH, the heat liberated is 114.64 kJ. What is the enthalpy of neutralization?

  • + 114.64 kJ

  • -114.64 kJ

  • -57.32 kJ

  • + 57.32 kJ


470.

What is the free energy change G when 10 moles of water at 100°C and 1 atm pressure is converted into steam at 100° C and 1 atm pressure?

  • 540 cal

  • -9800 cal

  • 9800 cal

  • 0 cal


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