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Using the identity (a - b) 2 = a 2 -2ab + b 2 We have (2a - 7 ) (2a - 7) = (2a - 7) 2 = (2a) 2 - 2(2a)(7) + (7) 2 = 4a 2 - 28a + 49

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Algebraic Expressions and Identities

Short Answer Type

91.

Consider the special case of Identity (IV) with b = –a. What do you get? It is related to Identity (III).

105 Views

92.

Use a suitable identity to get each of the following products.

(x + 3) ( x + 3)

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93.

Use a suitable identity to get each of the following products.

(2y + 5) (2y + 5)

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94.
Use a suitable identity to get each of the following products.

(2a - 7) (2a - 7)

Using the identity
(a - b)²= a²-2ab + b²

We have

(2a - 7 ) (2a - 7) = (2a - 7)²
                        = (2a)² - 2(2a)(7) + (7)²
                        = 4a² - 28a + 49

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95.

Use a suitable identity to get each of the following products.

$space space space space space space space space space space space space space space space space space space space space open parentheses 3 a minus 1 half close parentheses open parentheses 3 a minus 1 half close parentheses$

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96.

Use a suitable identity to get each of the following products.

(1.1m - 0.41) (1.1m + 0.4)

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97.

Use a suitable identity to get each of the following products.

(a²+ b²) (-a² + b²)

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98.

Use a suitable identity to get each of the following products.

(6x - 7) (6x + 7)

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99.

Use a suitable identity to get each of the following products.

(-a + c) (-a + c)

84 Views

100.

Use a suitable identity to get each of the following products.

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