Consider the special case of Identity (IV) with b = –a. What do you get? It is related to Identity (III).
Use a suitable identity to get each of the following products.
(1.1m - 0.41) (1.1m + 0.4)
Use a suitable identity to get each of the following products.
(a2 + b2) (-a2 + b2)
∵ (a2 + b2) (-a2 + b2) =(b2 + a2) (b2 - a2)
∴ ( a + b) (a - b) = a2 - b2 , we have
(b2 + a2)Â (b2 - a2) = (b2Â )2 - (a2Â )2
                          = b4 - a4