Trying to find the right answer to this..

we have 5p 2 q – 2pq 2 + 5pq – 11q – 3p + 28 4p 2 q + 5pq 2 – 3pq + 7q – 8p – 10 (-) (-) (+) (-) (+) (+) ________________________________ (5 -4) p 2 q + (-2 - 5) pq 2 + ( 5 + 3)pq + (-11 -7)q + (-3 + 8)p + (28 + 10) = (1)p 2 q + (-7)pq 2 + (8)pq + (-18)q + (5)p + (38) = p 2 q - 7pq 2 + 8pq - 18q + 5p + 38

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.

Algebraic Expressions and Identities

Short Answer Type

151.
Subtract 4p²q + 5pq² – 3pq + 7q – 8p – 10 from 5p²q – 2pq² + 5pq – 11q – 3p + 28

we have

5p²q – 2pq² + 5pq – 11q – 3p + 28
4p²q + 5pq² – 3pq + 7q – 8p – 10
(-)       (-)    (+)    (-)   (+) (+)
________________________________
(5 -4) p²q + (-2 - 5) pq²+ ( 5 + 3)pq + (-11 -7)q + (-3 + 8)p + (28 + 10)
      = (1)p²q + (-7)pq²+ (8)pq + (-18)q + (5)p + (38)
                              = p²q - 7pq²+ 8pq - 18q + 5p + 38