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We have (p + 2) x (5p 2 + 4p + 7) = p(5p 2 + 4p + 7) + 2(5p 2 + 4p + 7) = [(5 x p x q 2 ) +9 ( 4 xp x p) + ( p x 7)] +[(2 x 5 x p 2 ) + (2 x 4 x p) + (2 x7) = 15pq 2 + 5p 2 + 7p + 10p 2 + 8p + 14 = 15pq 2 + (5 + 10) p 2 + (7 + 8)p + 14 = 15pq 2 + 15p 2 + 15p + 14

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Algebraic Expressions and Identities

Short Answer Type

151.

Subtract 4p²q + 5pq² – 3pq + 7q – 8p – 10 from 5p²q – 2pq² + 5pq – 11q – 3p + 28

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152.
Find the product of (5p² + 4p + 7) and (p + 2).

We have (p + 2) x (5p²+ 4p + 7)

= p(5p²+ 4p + 7) + 2(5p²+ 4p + 7)
= [(5 x p x q²) +9 ( 4 xp x p) + ( p x 7)] +[(2 x 5 x p²) + (2 x 4 x p) + (2 x7)
= 15pq² + 5p²+ 7p + 10p²+ 8p + 14
= 15pq² + (5 + 10) p²+ (7 + 8)p + 14
= 15pq² + 15p²+ 15p + 14