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Short Answer Type

21. The surface area of a spherical bubble is increasing at the rate of 2 cm²/sec. Find the rate at which the volume of the bubble is increasing at the instant its radius is 6 cm.

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22.

The volume of a spherical balloon is increasing at the rate of 25 cm³/sec. Find the rate of change of its surface area at the instant when its radius is 5 cm.

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Long Answer Type

23. The radius of a spherical soap bubble is increasing at the rate of 0.3 cms^–1. Find the rate of change of its (i) volume (ii) surface area when the radius is 8 cm.

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24. The radius of a spherical soap bubble is increasing at the rate of 0.2 cms^–1. Find the rate of change of its (i) volume (ii) surface area, when the radius is 4 cm.

Let r be radius of spherical soap bubble.

therefore space space space space space space space space space space space space space dr over dt space equals space 0.2 space space cms to the power of negative 1 end exponent space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space... left parenthesis 1 right parenthesis

(i)

straight V space equals space 4 over 3 πr cubed space space space where space straight V space is space volume.

therefore space space space space space space space space space dV over dt space equals space fraction numerator 4 straight pi over denominator 3 end fraction cross times 3 straight r squared space dr over dt space equals space 4 space straight pi space straight r squared space cross times space 0.2 space space space space space space space space space space space space space space space space space open square brackets because space space space of space left parenthesis 1 right parenthesis close square brackets space space space space space space space space space space space space space space space space space space space space space space space equals space 0.8 space straight pi space straight r squared

When

straight r space equals space 4 comma space space dV over dt space equals space 0.8 space straight pi space cross times space 16 space equals space 12.8 space straight pi space cubic space cm divided by sec

(ii)

straight S space equals space 4 πr squared space space space where space straight S space is space surface space area

therefore space space space space space dS over dt space equals space 8 πr dr over dt space equals space 8 πr cross times 0.2 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space open square brackets because space space of space left parenthesis 1 right parenthesis close square brackets space space space space space space space space space space space space space space space space space space space equals space 1.6 space straight pi space straight r when space straight r space equals 4 comma space space space space dS over dt space equals space 1.6 space straight pi space cross times space 4 space equals space 6.4 space straight pi space sq. space cm divided by sec

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25. The radius of a spherical soap bubble is increasing at the rate of 0.4 cms^–1 Find the rate of change of its (i) volume (ii) surface area, when the radius is 10 cm.

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Short Answer Type

26.

A ballon which always remains spherical on inflation, is being inflated by pumping in 900 cubic centimetres of gas per second. Find the rate of which the radius of the balloon is increasing when the radius is 15 cm.

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27.

The volume of a cube is increasing at a rate of 9 cubic centimeters per second. How fast is the surface area increasing when the length of an edge is 10 centimeters?

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28.

The volume of a cube is increasing at a rate of 7 cubic centimeters per second. How fast is the surface area increasing when the length of an edge is 12 centimeters?

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29. The volume of a cube is increasing at the rate of 8 cm³/s. How fast is the surface area increasing when the length of an edge is 12 cm?

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30.

The length x of a rectangle is decreasing at the rate of 2 cm/s and the width y is increasing at the rate of 2 cm/s. When x = 12 cm and y = 5 cm, find the rate of change of (a) the perimeter and (b) the area of the rectangle.

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