An inverted cone has a depth of 10 cm and a base of radius 5 cm.

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsLong Answer Type

41. A point source of light along a straight road is at a height of ‘a’ metres. A boy ‘b’ metres in height is walking along the road. How fast is his shadow increasing if he is walking away from the light at the rate of c metres per minute?
151 Views

42.

Water is dripping out from a conical funnel, at the uniform rate of 2 cc/sec through a tiny hole at the vertex of the funnel. When the slant height of water is 5 cm, find the rate of decrease of the slant height of the water.

494 Views

43. Water is running into a conical vessel, 15 cm deep and 5 cm in radius, at the rate of 0.1 cm2/sec. When the water is 6 cm deep, find at what rate is
(i) the water level rising?
(ii) the water surface area increasing?
(iii) the wetted surface of the vessel increasing?
214 Views

Advertisement

44.

An inverted cone has a depth of 10 cm and a base of radius 5 cm. Water is poured into it at the rate of 3 over 2 straight c. straight c. space per space minute. Find the rate at which the level of water in the cone is rising when the depth is 4 cm.


Let α be the semi-vertical angle of the cone CAB whose height CO is 10 cm and radius OB = 5 cm. Then
tan space straight alpha space equals space 5 over 10 space equals space 1 half
tan space straight alpha space equals space fraction numerator straight O apostrophe straight B apostrophe over denominator CO apostrophe end fraction space equals space fraction numerator straight O apostrophe straight B apostrophe over denominator straight h end fraction
rightwards double arrow space space space space straight O apostrophe straight B apostrophe space space equals space straight h space tan space straight alpha



Let V be the volume of the water in the cone i.e. the volume of the cone CA 'B' after time t minutes and h be the height of water. Then,
                            straight V space equals space 1 third straight pi left parenthesis OB apostrophe right parenthesis squared space left parenthesis CO apostrophe right parenthesis
rightwards double arrow space space space space space space space space space space straight V space equals space 1 third πh cubed tan squared straight alpha
rightwards double arrow space space space space space space space space space space space space space space space space space straight V space equals space straight pi over 12 straight h cubed space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space open square brackets because space space space tan space straight alpha space equals space 1 half close square brackets
therefore space space space space space space dV over dt space space equals space straight pi over 12 space 3 space straight h squared space dh over dt space equals straight pi over 4 straight h squared dh over dt space
rightwards double arrow space space space space space space 3 over 2 space space equals space fraction numerator straight pi space straight h squared over denominator 4 end fraction space space dh over dt space space space space space space space space space space space space space space space space space space space space space space open square brackets because space space dV over dt space equals 3 over 2 cm cubed divided by minute space left parenthesis given right parenthesis close square brackets space
rightwards double arrow space space space space dh over dt space equals space 6 over πh squared
rightwards double arrow space space space space space open parentheses dh over dt close parentheses subscript straight h space equals space 4 end subscript space space equals space fraction numerator 6 over denominator straight pi left parenthesis 4 right parenthesis squared end fraction space equals space fraction numerator 3 over denominator 8 space straight pi end fraction space space cm divided by min. space
therefore space space space space required space rate space space equals space fraction numerator 3 over denominator 8 space straight pi end fraction cm divided by sec. space space space space space space space space space space space space space space
                       
335 Views

Advertisement
Advertisement
45. Water is running out of a conical funnel at the rate of 5 cm3/sec. If the radius of the base of the funnel is 10 cm and the altitude is 20 cm, find the rate at which the water level is dropping when it is 5 cm from the top.
475 Views

 Multiple Choice QuestionsMultiple Choice Questions

46. The rate of change of the area of a circle with respect to its radius r at r = 6 cm is
  • 10 straight pi
  • 12 straight pi
  • 8 straight pi
  • 8 straight pi
88 Views

47.

The total revenue in Rupees received from the sale of x units of a product is given by R(x) = 3x 2 + 36x + 5.

  • 116
  • 96

  • 90

  • 90

94 Views

48.

A cylindrical tank of radius 10 m is being filled with wheat at the rate of 314 cubic metre per hour. Then the depth of the wheat is increasing at the rate of 

  • m3/h

  • 0 · 1 m3/h
  • 1 · 1 m3/h
  • 1 · 1 m3/h
103 Views

Advertisement

 Multiple Choice QuestionsShort Answer Type

49. Prove that the tangents to the curve Y = x2 – 5x + 6 at the points (2, 0) and (3, 0) are at right angles.
122 Views

50.

Show that the tangent to the curve y = 7x3 + 11 at the points where x = 2 and x = – 2 are parallel.

87 Views

Advertisement