Water is running out of a conical funnel at the rate of 5 cm3/se

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 Multiple Choice QuestionsLong Answer Type

41. A point source of light along a straight road is at a height of ‘a’ metres. A boy ‘b’ metres in height is walking along the road. How fast is his shadow increasing if he is walking away from the light at the rate of c metres per minute?
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42.

Water is dripping out from a conical funnel, at the uniform rate of 2 cc/sec through a tiny hole at the vertex of the funnel. When the slant height of water is 5 cm, find the rate of decrease of the slant height of the water.

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43. Water is running into a conical vessel, 15 cm deep and 5 cm in radius, at the rate of 0.1 cm2/sec. When the water is 6 cm deep, find at what rate is
(i) the water level rising?
(ii) the water surface area increasing?
(iii) the wetted surface of the vessel increasing?
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44.

An inverted cone has a depth of 10 cm and a base of radius 5 cm. Water is poured into it at the rate of 3 over 2 straight c. straight c. space per space minute. Find the rate at which the level of water in the cone is rising when the depth is 4 cm.

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45. Water is running out of a conical funnel at the rate of 5 cm3/sec. If the radius of the base of the funnel is 10 cm and the altitude is 20 cm, find the rate at which the water level is dropping when it is 5 cm from the top.


Let r be the radius and h the height of the surface of water at time t. Let V be the volume of water in the funnel.
therefore space space space space straight V space equals space 1 third πr squared straight h                                   ...(1)
Also, by similar triangles, we have
          straight r over straight h space equals space 10 over 20 space space space space space space space space rightwards double arrow space space space space space straight r space equals space 1 half straight h
therefore space space space space from space left parenthesis 1 right parenthesis comma space space space straight V space equals space 1 third straight pi open parentheses straight h over 2 close parentheses squared space straight h space equals space πh squared over 12 space space space space space space space space space space space space space space space space space space space space space space space space space space... left parenthesis 2 right parenthesis
Since water is running out of the funnel at the rate of 5 space cm cubed divided by sec.
therefore space space space space space dV over dt space equals space minus 5 space space space space space space space space space space space space space space space space space space space open parentheses dV over dt space is space minus ve space because space straight V space decreases space as space straight t space increases close parentheses
From space left parenthesis 2 right parenthesis comma space space dt over dt space equals straight pi over 12 straight d over dt left parenthesis straight h cubed right parenthesis space equals space fraction numerator 3 πh cubed over denominator 12 end fraction dh over dt
therefore space space space minus 5 space equals space fraction numerator straight pi space straight h squared over denominator 4 end fraction dh over dt
therefore space space space space dh over dt equals negative fraction numerator 20 over denominator straight pi space straight h squared end fraction
therefore space space space rate space of space dropping space of space water space level space left parenthesis straight i. straight e. space of space straight h right parenthesis space straight w. straight r. straight t space time space straight t space equals space dh over dt space equals space fraction numerator negative 20 over denominator πh squared end fraction.
When space water space level space is space 5 space cm space from space the space top comma space space straight h space equals space 20 minus 5 space equals space 15.
therefore space space space space rate space of space dropping space of space water space level space straight w. straight r. straight t. space apostrophe straight t apostrophe space when space straight h space equals space 5 space is
space space space space space space space space space space space space space space space space space space space space space fraction numerator negative 20 over denominator straight pi left parenthesis 15 right parenthesis squared end fraction space equals space fraction numerator negative 20 over denominator straight pi cross times 225 end fraction space equals space fraction numerator negative 4 over denominator 45 space straight pi end fraction cm divided by sec.


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 Multiple Choice QuestionsMultiple Choice Questions

46. The rate of change of the area of a circle with respect to its radius r at r = 6 cm is
  • 10 straight pi
  • 12 straight pi
  • 8 straight pi
  • 8 straight pi
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47.

The total revenue in Rupees received from the sale of x units of a product is given by R(x) = 3x 2 + 36x + 5.

  • 116
  • 96

  • 90

  • 90

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48.

A cylindrical tank of radius 10 m is being filled with wheat at the rate of 314 cubic metre per hour. Then the depth of the wheat is increasing at the rate of 

  • m3/h

  • 0 · 1 m3/h
  • 1 · 1 m3/h
  • 1 · 1 m3/h
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 Multiple Choice QuestionsShort Answer Type

49. Prove that the tangents to the curve Y = x2 – 5x + 6 at the points (2, 0) and (3, 0) are at right angles.
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50.

Show that the tangent to the curve y = 7x3 + 11 at the points where x = 2 and x = – 2 are parallel.

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