Find the equation of the normal at the point (am2, am3) for the

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 Multiple Choice QuestionsShort Answer Type

61.

Find the slope of the normal at the point (am3 , am2 ) to the curve a x2 = y3.

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62.

Find a point on the curve y = (x – 2)2 at which the tangent is parallel to the chord joining the points (2, 0) and (4, 4).

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63.

Find the point at which the tangent to the curve straight y equals space square root of 4 straight x minus 3 end root space minus 1 has its slope 2 over 3.

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64.

Find the equation of the normal to the curve y2 = 4x at the point (1, 2).

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65.

Find the equation of tangent to the ellipse straight x squared over straight a squared plus straight y squared over straight b squared space equals space 1 space space space at space left parenthesis straight x subscript 1 comma space space straight y subscript 1 right parenthesis.

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66.

Find the equation of tangent and normal to the hyperbola straight x squared over straight a squared minus straight y squared over straight b squared space equals space 1 space space at space space left parenthesis straight x subscript 0 comma space space straight y subscript 0 right parenthesis.

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67. Find the equation of the normal at the point (am2, am3) for the curve ay= x3.


The equation of the curve is a y2 = x3
Differentiating both sides w.r.t. x,
                    2 ay dy over dx space equals space 3 straight x squared space space space space space space space space space space space space space space or space space space space space dy over dx space equals space fraction numerator 3 straight x squared over denominator 2 ay end fraction
At space left parenthesis am squared comma space space am cubed right parenthesis comma space space space dy over dx space equals space fraction numerator 3 space cross times space straight a squared space straight m to the power of 4 over denominator 2 space straight a space cross times space straight a space straight m cubed end fraction space equals space fraction numerator 3 straight a squared straight m to the power of 4 over denominator 2 straight a squared straight m cubed end fraction space equals space 3 over 2 straight m
which space is space slope space of space tangent.
therefore space space space space space space space space slope space of space normal space space equals space fraction numerator 2 over denominator 3 straight m end fraction
therefore space space space space space space the space equation space of space normal space at space left parenthesis am to the power of minus comma space space space space am cubed right parenthesis space is
space space space space space space space space space space space space space space space space space space straight y minus straight a space straight m cubed space equals space minus fraction numerator 2 over denominator 3 straight m end fraction left parenthesis straight x minus am cubed right parenthesis space space space or space space space space space space 3 my minus 3 am to the power of 4 space equals space minus 2 straight x plus 2 am squared
or space space space space space 2 straight x plus 3 my minus 3 am to the power of 4 minus 2 am squared space equals space 0
or space space space space space space 2 straight x plus 3 my minus am squared left parenthesis 3 straight m squared plus 2 right parenthesis space equals space 0

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68.

Find the equation of the tangent and the normal to the curve straight x to the power of 2 over 3 end exponent plus straight y to the power of 2 over 3 end exponent space equals space 2 space space at space left parenthesis 1 comma space 1 right parenthesis

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69.

Find the equation of the tangent and normal to the curve  y2 = 4ax at the point (at2, 2at).

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 Multiple Choice QuestionsLong Answer Type

70. Find the equation of the tangent and normal to the curve
straight x space equals space 1 minus cos space straight theta comma space space space space space straight y space equals space straight theta minus sin space straight theta space space space space at space straight theta equals space straight pi over 4
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