Find the equation of tangent and normal to the hyperbola  from

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 Multiple Choice QuestionsShort Answer Type

81.

Show that the normal at any point 0 to the curve
x = a cosө + a ө sinө. y = a sin ө – a ө cos ө
is at a constant distance from the origin.

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82.

Find the equation of the tangent and normal to the given curves at the points given:
y = x2 at (0,0).

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83.

Find the equation of the tangent and normal to the given curves at the points given:
y2 = 4ax at (0, 0).

89 Views

84.

Find the equation of the tangent and normal to the given curves at the points given:
y = x3 at (1, 1)

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85.

Find the equation of the tangent and normal to the given curves at the points given:
y = x2 at (2, 8)

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 Multiple Choice QuestionsLong Answer Type

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86.

Find the equation of tangent and normal to the hyperbola straight x squared over straight a squared minus straight y squared over straight b squared space equals space 1 space space space space at space the space point space space left parenthesis straight x subscript 0 comma space space space straight y subscript 0 right parenthesis


The equation of hyperbola is straight x squared over straight a squared minus straight y squared over straight b squared equals 1
Differentiating both sides w.r.t.x,
                  fraction numerator 2 straight x over denominator straight a squared end fraction minus fraction numerator 2 straight y over denominator straight b squared end fraction dy over dx space equals space 0 space space space space space space or space space space space space fraction numerator 2 straight y over denominator straight b squared end fraction dy over dx space equals space fraction numerator 2 straight x over denominator straight a squared end fraction space space space space space space space space space space space space space rightwards double arrow space space space space space dy over dx space equals space straight b squared over straight a squared straight x over straight y
At left parenthesis straight x subscript 0 comma space space straight y subscript 0 right parenthesis comma space   dy over dx space equals space straight b squared over straight a squared straight x subscript 0 over straight y subscript 0 comma space space which space is space slope space of space tangent. space
therefore space space space space space the space equation space of space tangent space at space left parenthesis straight x subscript 0 comma space space straight y subscript 0 right parenthesis space is
space space space space space space space space space straight y minus straight y subscript 0 space equals space straight b squared over straight a squared straight x subscript 0 over straight y subscript 0 left parenthesis straight x minus straight x subscript 0 right parenthesis
or space space space space space space straight y subscript 0 over straight b squared left parenthesis straight y minus straight y subscript 0 right parenthesis space equals space straight x subscript 0 over straight a squared left parenthesis straight x minus straight x subscript 0 right parenthesis space space or space space space space space space fraction numerator straight y space straight y subscript 0 over denominator straight b squared end fraction space minus space straight y subscript 0 squared over straight b squared space equals space fraction numerator straight x space straight x subscript 0 over denominator straight a squared end fraction minus straight x subscript 0 squared over straight a squared
or space space space space space space space space fraction numerator straight x space straight x subscript 0 over denominator straight a squared end fraction minus fraction numerator straight y space straight y subscript 0 over denominator straight b squared end fraction space equals space straight x subscript 0 squared over straight a squared minus straight y subscript 0 squared over straight b squared
or space space space space space space space xx subscript 0 over straight a squared minus fraction numerator straight y space straight y subscript 0 over denominator straight b squared end fraction space equals space 1 space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space space open square brackets table row cell because space space space space left parenthesis straight x subscript 0 comma space space straight y subscript 0 right parenthesis space lies space on space straight x squared over straight a squared minus straight y squared over straight b squared space equals space 1 end cell row cell therefore space space space space straight x subscript 0 squared over straight a squared minus straight y subscript 0 squared over straight b squared space equals space 1 end cell end table close square brackets

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 Multiple Choice QuestionsShort Answer Type

87. Find the equation of the normal at the point (am2, am3) for the curve ay= x3.
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88.

Find the equation of the tangent and the normal to the curve straight x to the power of 2 over 3 end exponent plus straight y to the power of 2 over 3 end exponent space equals space 2 space space space at space space left parenthesis 1 comma space 1 right parenthesis.

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89. Find the equation of the tangent and normal to the curve y2 = 4ax at (at2, 2at)
78 Views

 Multiple Choice QuestionsLong Answer Type

90.

Find the equation of the tangent and normal to the curve
straight x equals space 1 minus cos space straight theta comma space space space space straight y space equals space straight theta space minus sin space straight theta space space space at space straight theta space equals space straight pi over 4

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