Find points on the curve at which the tangents are (i) parallel to the x-axis (ii) parallel to the y-axis.
Find points on the curve at which the tangents are (i) parallel to the x-axis (ii) parallel to the y-axis.
For the curve y = 4x3 – 2x5, find all the points at which the tangent passes through the origin.
The equation of curve is
y = ax3 + bx2 + cx + 5 ...(1)
It meets y-axis at Q where x = 0 putting x = 0 in (1), we get,
...(2)
Also (-2, 0) lies on (1)
or
Subtracting (3) from (2), 4 a +2 = 0
From (2), -6 - 4b + 3 = 0
If the curve αx2 + βy2 = 1 and α' x2 + β'y2 = 1 intersect orthogonally, prove that (α – α') β β') = (β – β') α α'.