Find the maximum and minimum values, if any, of the following functions without using the derivatives:
– (x – 1)2 + 10
Let f (x) = – (x – 1)2 + 10
Now (x – 1 )2 ≥ 0 ∀ x ∊ R
⇒ – (x – 1)2 ≤ 0 ∀ x ∊ R ⇒ – (x – 1)2 + 10 ≤ ∀ x ∊ R
∴ maximum value of f (x) is 10. It has no minimum value.
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