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Let f (x) = x 4 – 62x 2 + ax + 9 f ' (x) = 4x 3 – 124x + a ∴ f ' (1) = 4 – 124 + a = – 120 + a ∴ f (x) attains max. value at x = 1 ∴ f ' (1) = 0 ⇒ – 120 + a = 0 ⇒ a – 120.

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Let f (x) = x⁴ – 62x² + ax + 9
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∴ f ' (1) = 4 – 124 + a = – 120 + a
∴ f (x) attains max. value at x = 1
∴ f ' (1) = 0 ⇒ – 120 + a = 0 ⇒ a – 120.

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