A jet of an enemy is flying along the curve y = x2 + 2. A sold

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299.

A jet of an enemy is flying along the curve y = x2 + 2. A soldier is placed at the point (3, 2). What is the nearest distance between the soldier and the jet?


Let (x, y) be any point on y = x2 + 2 at which jet is at a particular moment.
∴  jet is at (x, x2 + 2)
Let d be the distance between the jet at (x, x2 + 2) and solider at (3, 2).
∴  d2 = (x – 3)2 + [ (x2 + 2) – 2]2 = (x – 3)2 + (x2)2
  d2 = x4 + x2 – 6 x + 9
Let f (x) = d2 = x4 + x2 – 6 x + 9
f ' (x) = 4 x3 + 2 x – 6 = 2 (2 x3 + x – 3) = 2 (x – 1) (2 x2 + 2 x + 3)
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rightwards double arrow space space space space straight x space equals space 1 comma space space fraction numerator negative 2 plus-or-minus square root of 4 minus 24 end root over denominator 4 end fraction space equals 1 comma space space space fraction numerator negative 2 plus-or-minus 2 space straight i square root of 5 over denominator 4 end fraction
⇒ x = 1 as we reject imaginary values of x.
f ' ' (x) = 12 x+ 2
At x = 1, f ' ' (x) = 12 + 2 = 14 > 0 ⇒ f (x) has a local minimum at x = 1
But x = 1 is only extreme point
∴ f (x) is minimum at x = 1
∴  nearest distance = d at x = 1
equals space square root of 1 plus 1 minus 6 plus 9 end root equals space square root of 5

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