Manufacturer can sell x items at a price of rupees  The cost p

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 Multiple Choice QuestionsShort Answer Type

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301.

Manufacturer can sell x items at a price of rupees open parentheses 5 minus straight x over 100 close parentheses space each. The cost price of x items is Rs. open parentheses straight x over 5 plus 500 close parentheses. Find the number of items he should sell to earn maximum profit. 


straight C space equals space straight x over 5 plus 500
space straight R space equals space open parentheses 5 minus straight x over 100 close parentheses space left parenthesis straight x right parenthesis space equals space 5 straight x minus straight x squared over 100
straight P space equals space straight R space minus space straight C space equals space 5 straight x minus straight x squared over 100 minus straight x over 5 minus 500
therefore space space space space straight P space equals space 24 over 5 straight x minus straight x squared over 100 minus 500
space space space space space dP over dx space equals space 24 over 5 minus straight x over 50

    dP over dx space equals 0 space space space space space rightwards double arrow space space space 24 over 5 minus straight x over 50 space equals space 0 space space space space space space rightwards double arrow space space space straight x over 50 space equals space 24 over 5
therefore space space space space space space space straight x space equals space 24 over 5 cross times 50 space equals space 240
space space space space fraction numerator straight d squared straight P over denominator dx squared end fraction space equals space minus 1 over 50
When space straight x space equals space 240 comma space space space space fraction numerator straight d squared straight P over denominator dx squared end fraction space equals space minus 1 over 50 less than 0
therefore space space space space straight P space is space maximum space when space straight x space equals space 240
therefore space space space space manufacturer space can space earn space maximum space profit comma space if space he space sells space 240 space mins. space

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302.

A firm has found from experience that its profit as a function of x, the amount produced, is given by
straight p left parenthesis straight x right parenthesis space equals space minus straight x cubed over 3 plus 729 space straight x space minus 2500 comma space space space 0 space less or equal than space straight x space less or equal than space 35.
Find the value of x that maximises the profit.

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303.

A beam of length l is supported at one end. If W is the uniform load per unit length, the bending moment M at a distance x from the end is given by straight M space equals 1 half space straight l space straight x space space minus space 1 half space straight W space straight x squared. maximum value. Find the point on the beam at which the bending moment has th

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 Multiple Choice QuestionsLong Answer Type

304. Given the sum of the perimeters of a square and a circle, prove that the sum of their areas is least when the side of the square is equal to the diameter of the circle.
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305.

A wire of length 36 cm is cut into two pieces. One of the pieces is turned in the form of a square and the other in the form of an equilateral triangle. Find the length of each piece so that the sum of the areas of the two be minimum.

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306. A figure consists of a semi-circle with a rectangle on its diameter. Given perimeter of the figure, find the dimensions in order that the area may be maximum.
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307.

A window consists of a semi-circle with a rectangle on its diameter. If the perimeter of the window is 30 metres, find the dimensions of the window in order that its area may be maximum.
Or
A window is in the form of a rectangle surmounted by a semi-circle. If the total perimeter of the window is 30 m. find the dimensions of the window so that maximum light is admitted.

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308. A window is in the form of a rectangle surmounted by a semi-circular opening. The total perimeter of the window is 10 m. Find the dimensions of the window to admit maximum light through the whole opening.
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309.

A wire of length 28 m is to be cut into two pieces. One of the pieces is to be made into a square and the other into a circle. What should be the length of the two pieces so that the combined area of the square and the circle is minimum?

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 Multiple Choice QuestionsShort Answer Type

310. A wire of length 25 m is to be cut into two pieces. One of the pieces is to be made into a square and the other into a circle. What would be the lengths of the two pieces, so,that combined area of the square and the circle is minimum?
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