Use differentials to approximate fourth root of 80. from Mathe

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsShort Answer Type

371. Use differentials to approximate:
open parentheses 25 close parentheses to the power of 1 third end exponent
79 Views

372. Use differentials to approximate:
left parenthesis 26.57 right parenthesis to the power of 1 third end exponent

80 Views

373. Use differentials to approximate:
cube root of 26


86 Views

374. Use differentials to approximate:
cube root of 63


83 Views

Advertisement
375. Use differentials to approximate:
cube root of 0.009


192 Views

376.

Use differentials to approximate fourth root of 82.

77 Views

377.

Use differentials to approximate fourth root of 15.

73 Views

378.

Use differentials to approximate fourth root of 255.

87 Views

Advertisement
Advertisement

379.

Use differentials to approximate fourth root of 80.


Take space straight y space equals space straight x to the power of 1 fourth end exponent comma space space space straight x space equals space 81 comma space space space space dx space equals space δx space equals negative 1 space space space space so space that space straight x space plus space δx space equals space 80
Now comma space space space straight y space plus space δy space equals space left parenthesis straight x plus δx right parenthesis to the power of 1 fourth end exponent space space space space space space space rightwards double arrow space space space space space space δy space equals space left parenthesis straight x plus δx right parenthesis to the power of 1 fourth end exponent minus straight y space equals space left parenthesis 80 right parenthesis to the power of 1 fourth end exponent minus 3
rightwards double arrow space space space space left parenthesis 80 right parenthesis to the power of 1 fourth end exponent space equals space δy plus 3                                             ...(1)
Now δy is approximately equal to dy
and space dy space equals space dy over dx dx space equals space 1 fourth straight x to the power of negative 3 over 4 end exponent dx space equals space fraction numerator 1 over denominator 4 straight x to the power of begin display style 3 over 4 end style end exponent end fraction dx space equals space fraction numerator 1 over denominator 4 left parenthesis 81 right parenthesis to the power of begin display style 3 over 4 end style end exponent end fraction left parenthesis negative 1 right parenthesis space equals space fraction numerator negative 1 over denominator 4 cross times 27 end fraction space equals space fraction numerator negative 1 over denominator 108 end fraction
therefore space space space space from space left parenthesis 1 right parenthesis comma space space space left parenthesis 80 right parenthesis to the power of 1 fourth end exponent space equals space minus 1 over 108 plus 3 space equals space 323 over 108.
83 Views

Advertisement
380.

Use differentials to approximate fourth root of 81.5.

90 Views

Advertisement