If f (x) = 3x4 + 4x3 - 12x2 + 12, then f(x) is from Mathematics

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 Multiple Choice QuestionsMultiple Choice Questions

501.

If y = 4x-5 is a tangent to the curve y2 = px3 + q at (2, 3), then

  • p = 2, q = - 7

  • p = - 2, q = 7

  • p = - 2, q = - 7

  • p = 2, q = 7


502.

A missile is fired from the fround level rises x metre vertically upwards in t second, where x = 100t - 252t2. The maximum height recahed is

  • 200 m

  • 125 m

  • 160 m

  • 190 m


503.

If the curves x2 = 9A(9 - y) and x2 = A(y + 1) intersect orthogonally, then the value of A is

  • 3

  • 4

  • 5

  • 7


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504.

If f (x) = 3x4 + 4x3 - 12x2 + 12, then f(x) is

  • increasing in (- , - 2) and in (0, 1)

  • increasing in (- 2, 0) and in (1, )

  • decreasing in (- 2, 0) and in (0, 1)

  • decreasing in (- , - 2) and in (1, )


B.

increasing in (- 2, 0) and in (1, )

 fx = 3x4 +4x3 - 12x2 + 12    f'(x) = 12x3 + 12x2 - 24x           = 12xx2 + x - 2           = 12xx - 1x +2

From above it is clear that

f'(x) is increasing in (- 2, 0) and in (1, ).


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505.

Gas is being pumped into a spherical balloon at the rate of 30 ft3/min. Then, the rate at which the radius increases when it reaches the value 15 ft is

  • 115π ft/min

  • 130π ft/min

  • 120 ft/min

  • 125 ft/min


506.

A point on curve xy2 = 1 which is at minimum distance from the origin is

  • (1, 1)

  • (1/4, 2)

  • (21/6, 2- 1/3)

  • (2- 1/3, 21/6)


507.

A spherical iron ball ofradius 10 cm, coated with a layer of ice of uniform thickness, melts at a rate of 100 π cm/min. The rate at which the thickness of decreases when the thickness of ice is 5 cm, is

  • 1 cm/min

  • 2 cm/min

  • 1376 cm/min

  • 5 cm/min


508.

If ax2 + bx + 4 attains its minimum value - 1 at x = 1, then the values of a and bare respectively

  • 5, - 10

  • 5, - 5

  • 5, 5

  • 10, - 5


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509.

The function f(x) = (9 - x2)2 increases in

  • - 3, 0  3, 

  • - , - 3  3, 

  • - , - 3  0, 3

  • (- 3, 3)


510.

Let gx = 2e,             if x  1logx - 1, if x > 1. The equation  of the normal to y = g(x) at the point (3, log(2)), is

  • y - 2x = 6 + log(2)

  • y + 2x = 6 + log(2)

  • y + 2x = 6 - log(2)

  • y + 2x = - 6 + log(2)


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