If the function f(x) = x3 -12ax2 + 36a2x - 4(a > 0) attains its maximum and minimum at x = p and x = q respectively and if 3p = q2, then a is equal to
18
A.
Given, f(x) = x3 - 12ax2 + 36a2x - 4
On differentiating w.r.t. x, we get
f' (x) = 3x2 - 24ax + 36a2
Put f'(x) = 0 ⇒ 3(x2 - 8ax + 12a2) = 0
The equation of the tangent to the curve at the point where the curve crosses y-axis is equal to
3x + 4y = 16
4x + y = 4
x + y = 4
4x - 3y = - 12
The diagonal of a square is changing at the rate of 0.5 cms-1. Then, the rate of change of area, when the area is 400 cm2 is equal to
The equation of the tangent to the curve x2 - 2.xy + y2 + 2x + y - 6 = 0 at (2, 2) is
2x + y - 6 = 0
2y + x - 6 = 0
x + 3y - 8 = 0
3x + y - 8 = 0
The point on the curve x2 + y2 = a2, y 0 at which the tangent is parallel to x-axis is
(a, 0)
(- a, 0)
(0, a)