The equation of tangent to the curve y = x3 - 6x + 5 at (2, 1) is

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 Multiple Choice QuestionsMultiple Choice Questions

551.

The slope of the curve y = excos(x), x  - π, π is maximum at

  • x = π2

  • x = - π2

  • x = π4

  • x = 0


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552.

The equation of tangent to the curve y = x3 - 6x + 5 at (2, 1) is

  • 6x - y - 11 = 0

  • 6x - y - 13 = 0

  • 6x + y + 11 = 0

  • 6x - y + 11 = 0


A.

6x - y - 11 = 0

The equation of the curve y = x3 - 6x + 5

          dydx = 3x2 - 6 dydx2, 1 = 6Now, equation of the tangent at (2, 1) is              (y - 1) = 6(x - 2)            y - 1 = 6x - 12 6x - y - 11 = 0


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553.

Let f(x) = 2x3 - 5x2 - 4x + 3, 12  x  3. The point at which the tangent to the curve is parallel to the X-axis, is

  • (1, - 4)

  • (2, - 9)

  • (2, - 4)

  • (2, - 1)


554.

Two sides of triangle are 8 m and 56 m in length. The angle between them is increasing at the rate 0.8=08  rad/s. When the angle between sides of fixed length is π3, the rate at which the area of the triangle is increasing, is

  • 0. 4 m2/s

  • 0.8 m2/s

  • 0 . 6 m2/s

  • 0.04 m2/s


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555.

If y = 8x- 60x2 + 144x + 27 is a decreasing function in the interval

  • (- 5, 6)

  • - , 2

  • (5, 6)

  • (2, 3)


556.

The minimum value of the function max (x, x) is equal to

  • 0

  • 1

  • 2

  • 1/2


557.

Let f(x) = 2x3 - 9ax2 + 12a2x + 1, where a > 0. The minimum of f is attained at a point q and the maximum is attained at a point p. If p = q, then a is equal to

  • 1

  • 3

  • 2

  • 0


558.

The difference between the maximum and minimum value of of the function fx = 0xt2 + t + 1dt on [2, 3] is

  • 39/6

  • 49/6

  • 59/6

  • 69/6


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559.

If a and b are the non-zero distinct roots of x2 + ax + b = 0, then the minimum value of x2 + ax + b is

  • 2/3

  • 9/4

  • - 9/4

  • - 2/3


560.

The equation of the tangent to the curve (1 + x2)y = 2 - x where it crosses the x-axis, is :

  • x + 5y = 2

  • x - 5y = 2

  • 5x - y = 2

  • 5x + y - 2 = 0


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