The area of the region enclosed between parabola y2 = x and the l

Previous Year Papers

Download Solved Question Papers Free for Offline Practice and view Solutions Online.

Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.
Advertisement

 Multiple Choice QuestionsMultiple Choice Questions

131.

Area of the region bounded by y = x and y = - x + 2 is

  • 4 sq units

  • 3 sq units

  • 2 sq units

  • 1 sq units


132.

The area of the region bounded by the curves y = x2 and x = yis

  • 1/3

  • 1/2

  • 1/4

  • 3


133.

If f(x) = x23, x  0. Then, the area of the region enclosed by the curve y = f (x) and the three lines y = x, x = 1and x = 8 is

  • 632

  • 935

  • 1057

  • 12910


134.

If f(x) = x1x - 1 + 1x + 1x + 1, x> 1. Then,

  • f(x)  1

  • 1 < f(x)  2

  • 2 < f(x)  3

  • f(x) > 3


Advertisement
Advertisement

135.

The area of the region enclosed between parabola y2 = x and the line y = mx is 148. Then, the value of m is

  • - 2

  • - 1

  • 1

  • 2


A.

- 2

D.

2

Equation of parabola is y2 = x and line y = mx

For intersection point of both curves put x = y2, we get

         y = my2  ymy - 1 = 0     y = 0 or y = 1mThen, x = 0 or x = 1m2

 Intersection points are 0, 0 and P1m2, 1m

 Required area= 01/mym - y2dy = y22m - y3301m= 12m3 - 13m3 = 16m3 = 148        as given

   16m3 = ± 148  m3 = ± 8Now, if m3 = 8       m3 = 23  m = 2If          m3 = - 8       m3 = - 23  m = - 2


Advertisement
136.

The area of the region bounded by the curves y = x , y = 1x, x = 2 is

  • 4 - loge2

  • 14 + loge2

  • 3 - loge2

  • 154 - loge2


137.

The area of the region, bounded by the curves y = sin- 1(x) + x(1 - x) and y = sin- 1 (x) - x(1 - x) in the first quadrant, is

  • 1

  • 12

  • 13

  • 14


138.

The area enclosed between y2 = x and y = x is

  • 23 sq unit

  • 12 unit

  • 13 unit

  • 16


Advertisement
139.

The area bounded by y2 = 4x and x = 4y is

  • 203 sq units

  • 163 sq units

  • 143

  • 103


140.

The area of the region bounded by y2 = x and y = x is

  • 13sq. unit

  • 16 sq. units

  • 23 sq. units

  • 1 sq. units


Advertisement