V A median of a triangle divides it into two triangles of equal areas
∵ E is the mid-point of AD
∴ BE is a median of ΔABD
∴ ar(ΔBED) = ar(ΔBEA) = 1/2 ar(ΔABD)
∵ A median of a triangle divides it into two triangles of equal areas
∵ F is the mid-point of AE ∴ BF is a median of ΔABE
[ A median of a triangle divides it into two triangles of equal areas]
In the given figure, ABED is a parallelogram in which DE = EC. Show that area (ABF) = area (BEC)
In the following figure, ABCD is a parallelogram and EFCD is a rectangle. Also, AL ⊥ DC. Prove that
(i) ar(ABCD) = ar(EFCD)
(ii) ar(ABCD) = DC x AL.