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Areas of Parallelograms and Triangles

Long Answer Type

41. 8. XY is a line parallel to side BC of a triangle ABC. If BE || AC and CF || AB meet XY at E and F respectively, show that ar(ΔABE) = ar(ΔACF).

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42. The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q and then parallelogram PBQR is completed. Show that ar(||gm ABCD) = ar(||gm PBQR).

[Hint. Join AC and PQ. Now compare ar(ACQ) and ar(APQ)].

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Short Answer Type

43. Diagonals AC and BD of a trapezium ABCD with AB || DC intersect each other at O. Prove that ar(ΔAOD) = ar(ΔBOC).

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44.

In figure, ABCDE is a pentagon. A line through B parallel to AC meets DC produced at F. Show that
(i) ar(ΔACB) = ar(ΔACF)
(ii) ar(□AEDF) = ar(ABCDE).

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45. A villager Itwaari has a plot of land of the shape of a quadrilateral. The Gram Panchayat of the village decided to take over some portion of his plot from one of the comers to construct a Health Centre. Itwaari agrees to the above proposal with the condition that he should be given equal amount of land in lieu of his land adjoining his plot so as to form a triangular plot. Explain how this proposal will be implemented.

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46. ABCD is a trapezium with AB || DC. A line parallel to AC intersects AB at X and BC at Y. Prove that ar(ΔADX) = ar(ΔACY).

[Hint. Join CX.]

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47. In figure, AP || BQ || CR. Prove that ar(ΔAQC) = ar(ΔPBR).

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48. Diagonals AC and BD of a quadrilateral ABCD intersect at O in such a way that ar(ΔAOD) = ar(ΔBOC). Prove that ABCD is a trapezium.

Given: Diagonals AC and BD of a quadrilateral ABCD intersect at O in such a way that ar(ΔAOD) = ar(ΔBOC)

To Prove: □ABCD is a trapezium.
Proof: ar(ΔAOD) = ar(ΔBOC)
⇒ ar(ΔAOD) + ar(ΔAOB)
= ar(ΔBOC) + ar(ΔAOB)
| Adding the same areas on both sides
⇒ ar(ΔABD) = ar(ΔABC)
But ΔABD amd ΔABC are on the same base
AB.
∴ ΔABD and ΔABC will have equal corresponding altitudes.
ΔABD and ΔABC will lie between the same parallels.
∴ AB || DC
∴ [□ABCD is a trapezium.
A quadrilateral is a trapezium if exactly one pair of opposite sides is parallel

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