For what value of n, are the nth terms of two APs: 63, 65, 67, . . . and 3, 10, 17, . . . equal?
Find the sum of the following APs:
0.6, 1.7, 2.8, . . ., to 100 terms.
Here a = 0.6
d = 1.7 – 0.6 = 1.1 And, n = 100 We know that,
= 50 x [2 x 0.6 + (100 - 1) x 1.1]
= 50 x [1.2 + 108.9]
= 50 x 110.1 = 5505.0
Hence, the sum of first 100 terms of the given
A.P. = 5505.