In an APgiven a = 7, a13 =35, find d and S13. from Mathematics

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64.

In an AP
given a = 7, a13 =35, find d and S13.


Here,  a = 7, a13 =35, find d and S13.
We know that, a= a + (n - 1)d
rightwards double arrow  a13 = 7 + (13 - 1)d
rightwards double arrow  35 = 7 + 12d
rightwards double arrow   35 - 7 = 12d
rightwards double arrow   12d = 28
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And comma space space space space straight S subscript 13 equals 13 over 2 open square brackets 2 cross times 7 plus left parenthesis 13 minus 1 right parenthesis cross times 7 over 3 close square brackets
space space space space space space space space space space space space space space space space space space space space open square brackets because space straight S subscript straight n equals straight n over 2 left square bracket 2 straight a plus left parenthesis straight n minus 1 right parenthesis straight d close square brackets
space space space space space space space space space space space space space space space equals 13 over 2 left square bracket 14 plus 28 right square bracket
space space space space space space space space space space space space space space space equals space 13 over 2 cross times 42 equals 13 cross times 21 equals 273
Hence comma space space space space straight d space space space equals 7 over 3 space and space straight S subscript 13 equals 273
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