We have, an = –62,a = 10 and d = –3 Now an = a + (n – 1)d⇒ –62 = 10 + (n – 1) (– 3)⇒ – 62 = 10 – 3n +3⇒ – 62 = 13 – 3n⇒ –3n = –75⇒ n = 25Now middle term = a13 = a + 12d= 10 + 12(– 3)= 10 – 36 = – 26
How many two digit numbers are divisible by 3.