If the ratio of the sum of first n terms of two A.P’s is (7n +

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 Multiple Choice QuestionsShort Answer Type

341. The 17th term of an A .P. exceeds the 10th term by 7. Find the common difference.
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342. Two APs have the same common difference. The difference between their 100th terms is 100, what is the difference between their 100th terms?
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343.

For what value of k will k+9, 2k-1 and 2k+7 are the consecutive terms of an A.P?

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344.

The 4th term of an A.P. is zero. Prove that the 25th term of the A.P. is three times its 11th term.

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345.

If the ratio of the sum of first n terms of two A.P’s is (7n +1): (4n + 27), find the ratio of their mth terms.


Let a1, a2 be the first terms and d1 , d2 the common differences of the two given A.P's.
Then, we have Sn =straight S subscript straight n space equals straight n over 2 left square bracket 2 straight a subscript 1 plus left parenthesis straight n minus 1 right parenthesis straight d subscript 1 right square bracket space and space straight S subscript straight n equals straight n over 2 left square bracket 2 straight a subscript 2 plus left parenthesis straight n minus 1 right parenthesis straight d subscript 2 right square bracket
therefore straight S subscript straight n over straight S subscript straight n equals fraction numerator straight n over 2 left square bracket 2 straight a subscript 1 plus left parenthesis straight n minus 1 right parenthesis straight d subscript 1 right square bracket over denominator straight n over 2 left square bracket 2 straight a subscript 2 plus left parenthesis straight n minus 1 right parenthesis straight d subscript 2 right square bracket end fraction space equals fraction numerator 2 straight a subscript 1 plus left parenthesis straight n minus 1 right parenthesis straight d subscript 1 space over denominator 2 straight a subscript 2 plus left parenthesis straight n minus 1 right parenthesis straight d subscript 2 end fraction
It space is space given space that space
straight S subscript straight n over straight S subscript straight n space equals fraction numerator 7 straight n plus 1 over denominator 4 straight n plus 27 end fraction
therefore space fraction numerator 2 straight a subscript 1 plus left parenthesis straight n minus 1 right parenthesis straight d subscript 1 space over denominator 2 straight a subscript 2 plus left parenthesis straight n minus 1 right parenthesis straight d subscript 2 end fraction equals fraction numerator 7 straight n plus 1 over denominator 4 straight n plus 27 end fraction space.. space left parenthesis 1 right parenthesis
To space find space the space ratio space of space the space straight m to the power of th space terms space of space the space tow space given space straight A. straight P apostrophe straight s space
replace space straight n space by space left parenthesis 2 straight m minus 1 right parenthesis space in space equation space 1
therefore space equals fraction numerator 2 straight a subscript 1 plus left parenthesis 2 straight m minus 2 right parenthesis straight d subscript 1 over denominator 2 straight a subscript 2 plus left parenthesis 2 straight m minus 2 right parenthesis straight d subscript 2 end fraction equals fraction numerator 14 straight m minus 7 plus 1 over denominator 8 straight m minus 4 plus 27 end fraction
therefore space fraction numerator straight a subscript 1 plus left parenthesis straight m minus 1 right parenthesis straight d subscript 1 over denominator straight a subscript 2 left parenthesis straight m minus 1 right parenthesis straight d subscript 2 end fraction space equals space fraction numerator 14 straight m minus 6 over denominator 8 straight m plus 23 end fraction
Hence comma space the space ratio space of space the space straight m to the power of th space terms space of space the space two space straight A. straight P apostrophe straight s space is space 14 straight m minus 6 colon 8 straight m plus 23

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346.

The houses in a row numbered consecutively from 1 to 49. Show that there exists a value of X such that sum of numbers of houses preceding the house numbered X is equal to the sum of the numbers of houses following X.

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347.

In an AP, if S5 + S7 = 167 and S10 = 235, then find the AP,  Where Sn denotes the sum of its first n terms.

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348.

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 Multiple Choice QuestionsLong Answer Type

349.

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 Multiple Choice QuestionsShort Answer Type

350.

Find how many integers between 200 and 500 are divisible by 8.

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